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Sati [7]
3 years ago
8

The transitive property holds for similar figures. True Faise

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
True..............☺️
navik [9.2K]3 years ago
5 0

Answer: TRUE

Step-by-step explanation: hope this helps

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Divide 489 into two parts such that the first part is 9 more than twice the second part. ​
blagie [28]
166 is the right awnser for this
5 0
3 years ago
Determine if the given function can be extended to a continuous function at xequals0. If​ so, approximate the extended​ function
Akimi4 [234]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The correct option is  A

Step-by-step explanation:

Now  from the question we are given the function

        f(x) =  \frac{10^{2 x} -4}{x}

Now  as  \lim_{x \to 0} [f(x) ] =  \frac{10^{2*0} -4 }{0}

       =>    \lim_{x \to 0} [f(x) ] = - \infty

This  implies that as x\to 0 the function f(x)  \to -\infty which means that at  x = 0  the function is not continuous  

3 0
4 years ago
4,12,20 find the 41st term
Irina-Kira [14]

Answer:

The 41st term of the given series is 324

Step-by-step explanation:

a= 4

a2= 12

d= a2-a

d= 12-4 = 8

now, we have to find 41 term that is a41

a41 = a+ 40d

a41= 4+ 40× 8

a41= 4+ 320

= 324

therefore the 41st term is 324

4 0
3 years ago
Read 2 more answers
40 points for question
Flauer [41]

Answer:

x is 12 i believe

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Function A is a quadratic function with a vertex at (3, 4) and a leading coefficient of -1 Function B has the equation y = |x +
skad [1K]

With the information given, we deduce that the parabola is

y=-(x-3)^2+4 = -(x^2-6x+9)+4 = -x^2+6x-5

Reflecting a function over the x axis means to change its sign. After the reflection, the parabola becomes

y=x^2-6x+5

And to shift down a function, you subtract the shift from the equation: the equation becomes

y=x^2-6x+5-2=x^2-6x+3

Similarly, the other function is reflected over the x axis (sign change) and shifted up 3 (add 3 to the equation):

|x+2|\mapsto -|x+2|\mapsto -|x+2|+3

In order to compute the y intercept, we simply have to evaluate the functions at x=0: for the parabola we have

y(0)=3

For the other function, we have

y(0)=-|2|+3=-2+3=1

8 0
4 years ago
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