Answer:
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>- integration
- PEMDAS
Which equation represents the function graphed on the coordinate plane?
2 answers:
Answer:
<h2>B. g(x) = |x + 4| – 10.</h2>Step-by-step explanation:
The second option shows the function represented in the given graph.
Basically, the graph shows an absolute value function, because it has the form of a "V".
We know that the parent function of this is , which is the simplest form of a value absolute function. So, we can get the right answer by just applying all given transformations to the parent function.
In the graph we see that the function was move 10 units downside, and 4 units to the left. This means that the function has to have "-10" and "+4", where the negative indicates the downside movement, and the positive sign indicates the left-side movement.
It's important to remember that, in case of horizontal displacement, with add to move to the left, and we subtract to move to the right.
Applying these translation to the parent function, we have
Therefore, the right answer is option B.
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Answer:
So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
Step-by-step explanation:
In this data we have
Mean= u = 18
X= 38
Standard deviation = s= 6
1) We formulate the null and alternate hypothesis as
H0: u = 18 against Ha : u > 18 One tailed test .
2) The significance level alpha = ∝= 0.05 and Z alpha has a value ± 1.645 for one tailed test.
3)The test statistics used is
Z= X- u / s
z= 38-18/6= 3.333
4) The calculated value of z = 3.33 is greater than the z∝ = 1.645
5) So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
First we set the criteria for determining the true of value of the variable. That whether the rats learn in less or more than 18 trials.
Then we find the value of z for the given significance value given and the test about to be checked.
Then the test statistic is determined and calculated.
Then both value of z and z alpha re compared. If the test statistics falls in the rejection region reject the null hypothesis and conclude alternate hypothesis is true.
The figure shows that the calulated z value lies outside the given z values
