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Stella [2.4K]
2 years ago
8

Which number line best shows how to solve -4-(-8)

Mathematics
1 answer:
Rama09 [41]2 years ago
7 0

Answer:

The first point should be plotted at -4, then there should be a line that goes up 8 units and gives us a final destination of 4.

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If A = 3x power 2+2y + 2 and B=6x power 2 - 8y + 1 then A+B and A-B​
ollegr [7]

Answer:

see explanation

Step-by-step explanation:

Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then

A + B

= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms

= 9x² - 6y + 3

-------------------------------

A - B

= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1

= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms

= - 3x² + 10y + 1

5 0
2 years ago
7 - r/8 - 3d <br><br><br><br> Variables <br><br> r=32 and d= 2
satela [25.4K]

The required value if r = 32 and d = 2 is -3

Given the expression

7-\frac{r}{8} - 3d

Substituting the given variables

r = 32

d = 2

The expression becomes

= 7-\frac{32}{8} - 3(2)\\= 7 - 4 - 6\\= 3 - 6\\= -3

Hence the required value is -3

Learn more here: brainly.com/question/17499155

6 0
2 years ago
Suppose a group of x people rent a log cabin for $320 for a weekend in the mountains and plan to share the cost equally. If one
Zanzabum

320/16 - 1 = 19 ppl hope i helped


8 0
3 years ago
Read 2 more answers
2(5x+3) ? what is the question ​
Delicious77 [7]

Hey there!

“2 (5x + 3)”

• FIRST and ONLY STEP: DISTRIBUTE 2 to ALL OF YOUR NUMBERS in the parentheses

2(5x) + 2(3)

2(5x) = 10x ⬅️ FRONT number

2(3) = 6 ⬅️ BACK number

BOTH OF YOUR NUMBERS ARE POSITIVE SO WE DON’T HAVE TO CHANGE ANYTHING

Answer: 10x + 6 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

3 0
2 years ago
Read 2 more answers
Find the area of the shaded region. Round to the nearest hundredth where necessary (2 decimal places
suter [353]

Answer:

117 in²

<u>Finding the area of the trapezoid:</u>

First, we need to find the area of the trapezoid formed by the dotted lines. The formula for finding the area of the trapezoid is "(a₁ + a₂)h/2".

[Where, a₁ = shorter parallel side; a₂ = longer parallel side]

⇒ (a₁ + a₂)h/2 = Area of trapezoid

⇒ (14 + 26)15/2 = Area of trapezoid

⇒ Area of trapezoid = (40)15/2 = (20)15 = 300 in²

<u>Reviewing on how to find the area of the unshaded region:</u>

To find the area of the shaded region, we need to subtract the area of the unshaded region from the area of the trapezoid. In this case, the unshaded region is a triangle whose base is 26 inches. To find the area of the triangle, we need to use the formula 1/2 x Base x Height. We are given the base, but the height is unknown.

<u>Determining the height:</u>

We are given a small side length "6 inches" and the height of the trapezoid "15 inches". If we subtract the small side length from the height of the trapezoid, we will obtain the height of the triangle.

⇒ Height of trapezoid - Small side length = Height of triangle

⇒ 15 - 6 = Height of triangle

⇒ 9 in = Height of triangle

<u>Determining the area of the unshaded region:</u>

Now, let's substitute the base and the height in the formula to find the area of the triangle

⇒ 1/2 x Base x Height

⇒ 1/2 x 26 x 9

⇒ 13 x 9

⇒ 117 in²

<u>Determining the area of the shaded region:</u>

Finally, let's subtract the area of the unshaded region from the area of the trapezoid to obtain the area of the shaded region.

⇒ Area of trapezoid - Area of unshaded region = Area of shaded region

⇒ 300 - 117 = Area of shaded region

⇒ 183 in² = Area of shaded region

5 0
1 year ago
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