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prisoha [69]
3 years ago
9

At the end of the car lease, you pay a certain amount if you decide to buy the car. What is this amount called? A. interest B. l

ease amount C. residual value
Mathematics
2 answers:
blondinia [14]3 years ago
5 0
I would say C or b because they make more sense then a
Annette [7]3 years ago
5 0

Answer:

C. residual value is the answer.

Step-by-step explanation:

At the end of the car lease, you pay a certain amount if you decide to buy the car. This amount is called residual value. When a person leases a car,he pays for that portion of the car's value that he uses. If he wants to purchase that car after lease period over, then he will pay the price for the remaining portion of the car's value. Hence, residual value is the answer.

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vaieri [72.5K]

Answer:

r^5

Step-by-step explanation:

6 0
3 years ago
Catalina and Morgan are finding the length of the third side of the right triangle. Who is correct? Explain your reasoning.
algol13

Answer:

Morgan

Step-by-step explanation:

because the pythagoras theorem is

H

{h1}^{2}  =  {b}^{2}  +   {h2}^{2}

where h1=hypotenuse

h2=height

b=base

5 0
2 years ago
Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).
Firdavs [7]

Answer:

A) Particular solution:

2x+\frac{1}{2}e^{-x}-\frac{8}{5}

B) Homogeneous solution:

y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))

C) The most general solution is

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

Step-by-step explanation:

Given non homogeneous ODE is

y''+4y'+5y=10x+e^{-x}---(1)

To find homogeneous solution:

D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)

To find particular solution:

y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\

Substituting y_{p},y'_{p},y''_{p} in (1)

y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\

Equating the coefficients

5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\

The general solution is

y=y_{h}+y_{p}

from (2) ad (3)

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

6 0
3 years ago
And he runs the same number of miles ask every day. His total distance run for one week is less than 60 miles. Which any quality
stiv31 [10]

Answer:

around 8 or 8.5 miles a day for 7 days

Step-by-step explanation:

60 divided 7 equals 8.5

3 0
3 years ago
What is the solution to the system of equations?
irina [24]

Answer:

The solution is the point (6,-8)

Step-by-step explanation:

we have that

The first equation is y=(1/3)x-10 instead y=x-10

y=(1/3)x-10 -----> equation A

2x+y=4 -----> equation B

Solve the system of equations by substitution

Substitute equation A in equation B and solve for x

2x+[(1/3)x-10]=4

(7/3)x=14

x=6

Find the value of y

y=(1/3)(6)-10=-8

therefore

The solution is the point (6,-8)

4 0
4 years ago
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