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3 years ago

A baseball diamond is a square that is 90% on each side. If a player throws the ball from 2" base to home, how

Mathematics

1 answer:

Flura [38]3 years ago

5 0

Answer:

45 ft

Step-by-step explanation:

if each side is 90% and 2nd base is half way you divide 90 by 2

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Square root 1.96? is rational irrational

Kruka [31]

Answer:

Rational

Step-by-step explanation:

An irrational number is a number with forever continuing decimals. Plug it into the calc and you can see if there is a long decimal line that ends. You should get 1.4 in the calc, and since it does end, it is a rational number.

4 0

3 years ago

Here’s the answer you need to know

vovikov84 [41]

Thank you sooo much Maddi441

8 0

3 years ago

Please help I will increase the amount of points for every question answered

Rasek [7]

Answer:

Rate of Change = 4

Step-by-step explanation:

The starting point (x=0) is (0, -2)

The ending point (x=2) is (2, 6)

The distance between the two points in rise over run terms is 8/2

$\frac{8}{2} =4=rate$

8 0

3 years ago

Pls help I’ve been stuck on this for a while

White raven [17]

Answer:

Maybe 60

Step-by-step explanation:

I don't know just please guess sorry but can you mark as brainiest.

7 0

3 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is 1 ton i.e. 2000 lbs.

Let x be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

3 years ago