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3 years ago

Steel loading ramps are used to load a

Mathematics

1 answer:

tia_tia [17]3 years ago

6 0

Answer:

6.25 feet.

Step-by-step explanation:

Let L be the length of the ramp in feet.

We have been given that steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. The ramp make a 30° angle with the ground.

We can see from our attachment that ramp and truck bed forms a right triangle with ground. The truck bed is opposite side and length of ramp is hypotenuse of our given angle.

Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use Sine to solve for L.

Upon substituting our given values in above formula we will get,

Therefore, the length of the ramp is 75 inches.

Let us convert the length of ramp in feet.

1 feet = 12 inches.

Therefore, the length of the ramp is 6.25 feet.

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3 years ago

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132, 390, 244, 492

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2 years ago

The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in

wlad13 [49]

Step-by-step explanation:

<h2>☼︎Given :</h2>

The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

$\rule{200pt}{3pt}$

Area of the room.

$\rule{200pt}{3pt}$

<h2>☼︎Solution :</h2>

~ Formula Used:

$\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

~ Calculating the Area of Tiles 

${➙ \: {\sf{ Area = Length \times Breadth}}}$

${➙ \: {\sf{ Area = 30 \times 20 }}}$

${\sf{➙ \: Area \: of \: 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating Area of the Drawing Room :

${➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}}$

${➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}}$

${\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Therefore :

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

$\begin{gathered} \\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}\end{gathered}$

8 0

3 years ago

Read 2 more answers

1. Calculate the volume of a cube with the following measurements. Length = 5 cm Height = 10 cm Width = 16 cm 800 cubic cm 400 c

Finger [1]

Answer:

800

Step-by-step explanation:

lol ain't even a cube das a rectangle

3 0

3 years ago

Select True or False from each pull-down menu, depending on whether the corresponding statement is true or false.

Schach [20]

Answer:

1) FALSE

2) FALSE

3) TRUE

4) TRUE

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part 1

The mean and standard deviation of a normally distributed random variable which has been standardized are one and zero, respectively.

The mean and the deviation for the normal standard distribution are:

$\mu=0, \sigma =1$

So then that's FALSE.

Part 2

Using the standard normal curve, the z−score representing the 10th percentile is 1.28.

We are looking for a value a, that satisfy this:

$P(X>a)=0.90$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.10 and P(Z>-1.28)=0.90

So that's FALSE.

Part 3

Let z1 be a z−score that is unknown but identifiable by position and area. If the symmetrical area between −z1 and +z1 is 0.9544, the value of z1 is 2.0

If we find this probability:

$P(-2.0< Z$

So on this case we can approximate to 0.9544. And that's TRUE.

Part 4

Using the standard normal curve, the z−score representing the 75th percentile is 0.67.

We are looking for a value a, that satisfy this:

$P(X>a)=0.25$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.67. On this case P(Z<0.67)=0.75 and P(Z>0.67)=0.25

So that's TRUE.

3 0

4 years ago