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mariarad [96]
2 years ago
5

Recursive formula for a geometric sequence with a starting value of 8 and a common ratio of 5

Mathematics
1 answer:
Alexxx [7]2 years ago
5 0
a_2=5a_1
a_3=5a_2
a_4=5a_3
...
a_n=5a_{n-1}

So the recursive formula is

\begin{cases}a_1=8\\a_n=5a_{n-1}&\text{for }n>1\end{cases}
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NEED HELP ASAP<br> Solve 4 – x = –8.
Anna71 [15]

Answer:

i think it is 12 positive

Step-by-step explanation:

i think

4 0
3 years ago
Can someone fr help me with this like right now i’ll appreciate it sm
rjkz [21]

Step-by-step explanation:

Since

\frac{108}{72}  =  \frac{3}{2}

\frac{72}{48}  =  \frac{3}{2}

\frac{48}{32}  =  \frac{3}{2}

The function has a constant factor so we have a exponential function.

The equation of a exponential function is

y = a(b) {}^{x}

Where a is the initial value and b is the growth factor

The growth factor is 3/2,

The initial value in 32

y =  32 ( \frac{3}{2} ) {}^{x}

Plug in 4 for x.

You will get 162

Plug in 5 for x you will get

243.

2013- 162

2014- 243

8 0
1 year ago
Is this a parallelogram? Just checking
natka813 [3]

Answer:

Step-by-step explanation:

Yes it’s parallel because the lines do not meet

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
Please help! i literally suck at geometry
sdas [7]
Don’t say like that!Think you can and you will achieve! :) :)
8 0
2 years ago
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