Question

Recursive formula for a geometric sequence with a starting value of 8 and a common ratio of 5

Answer 1

$a_2=5a_1$
$a_3=5a_2$
$a_4=5a_3$
...
$a_n=5a_{n-1}$

So the recursive formula is

$\begin{cases}a_1=8\\a_n=5a_{n-1}&\text{for }n>1\end{cases}$