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mariarad [96]
3 years ago
5

Recursive formula for a geometric sequence with a starting value of 8 and a common ratio of 5

Mathematics
1 answer:
Alexxx [7]3 years ago
5 0
a_2=5a_1
a_3=5a_2
a_4=5a_3
...
a_n=5a_{n-1}

So the recursive formula is

\begin{cases}a_1=8\\a_n=5a_{n-1}&\text{for }n>1\end{cases}
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Calculus(Derivatives):
Zigmanuir [339]
f(x)=x^3+x^2-5x-2
\implies f'(x)=3x^2+2x-5=(3x+5)(x-1)

Critical points occur when f'(x)=0, which happens for x=-\dfrac53 and x=1.

Check the sign of the second derivative at each critical point to determine the function's concavity at that point. If it's concave (f''(x)), then a maximum occurs; if it's convex (f''(x)>0), then a minimum occurs.

You have

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