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3 years ago

2x+3y=6, what is the rate of change

Mathematics

1 answer:

ankoles [38]3 years ago

6 0

Answer:

-2/3

Step-by-step explanation:

rate of change is slope

so rearrange the equation to get in y = mx + b format

2x + 3y = 6

move the 2x over by subtraction

3y = -2x + 6

now divide by 3 to get y by itself

y = -2/3x + 2

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Simplify. 7x +84/(x + 12)(x+10)

Tasya [4]

Answer:

{7x^2+168x+840}/{x+12}

Step-by-step explanation:

3 0

3 years ago

Please help mee

NemiM [27]

(2^6)^x=1
(4)^x=1
(4)^0=1
1=1
X=0

(5^0)^x=1
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5 0

2 years ago

confirm or disprove ernest's work by selecting two different points and applying the slope formula. be sure to identify the poin

yan [13]

Answer:

Part a) Ernest's calculation was correct

Part b) Ernest's calculation was correct

Step-by-step explanation:

The picture of the question in the attached figure

The complete question is

Ernest calculated the slope of the graph during the uphill climb to be 10. His work is shown below.

Points: (60.900). (15, 450)

Slope : 900-450/60-15=450/45=10

Part a) Determine whether his calculation was correct or incorrect, and then explain why.

Part b) Confirm or disprove Ernest's work by selecting two different points and applying the slope formula. be sure to identify the points you chose

Part a)

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have the points

A(60,900),B(15,450)

Remember that

$m_A_B=m_B_A$

step 1

Find $m_A_B$

substitute in the formula

$m_A_B=\frac{450-900}{15-60}\\\\m_A_B=\frac{-450}{-45}=10$

step 2

Find $m_B_A$

substitute in the formula

$m_B_A=\frac{900-450}{60-15}\\\\m_B_A=\frac{450}{45}=10$

therefore

Ernest's calculation was correct, because $m_A_B=m_B_A$

Part b) selecting two different points

we take the points

(0,300) and (50,800) -----> see the attached figure

substitute in the formula of slope

$m=\frac{800-300}{50-0}$

$m=\frac{500}{50}$

$m=10$

therefore

Ernest's calculation was correct

8 0

3 years ago

Mrs. Gilus is in charge of the budget for the school. Last year, we began the year with &708.88 in our bank account, but by

liberstina [14]

It sounds like they had $708.88 at the beginning, however by the end of the year they OWED $347.99. The first number is in the positive while the other is a negative. Add the last number to the first number for the amount that they have spent which would be $1,056.87.

8 0

3 years ago

I need help with this

andre [41]

Answer:

$f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}$

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

Taken altogether, these factors give us the function ...

$\boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}$

8 0

3 years ago