Question

I need help please and thank you

Answer 1

Corresponding parts of similar triangles are proportional. The area of a triangle is 1/2bh. So DEF’s height is.

6 = 0.5(4h)
12 = 4h
h = 3

We know, therefore, that the ratio of ABC to DEF’s dimensions is 12:4, 3:1. With this, we can deduce that ABC’s height is 9 ( 3 x 3), so ABC’s area is:

0.5(12 x 9) = 54 sq ft

Answer 2

Well I THINK triangle ABC is just a stretched out version of triangle DEF.

To find the area of a triangle, you multiply base and height, and divide by 2.

Area of DEF is 6, so that means that (4 * x)/2 = 6.

6*2 = 12....

4 * x = 12........

4 * 3 = 12.

x = 3.

Comparing DEF to ABC: ABC's base is 3 times as long as DEF's. So that means the height must be three times as long.

3*3 = 9.

(12 * 9)/2 =54