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Andrei [34K]
3 years ago
8

Correct answer.

Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

The cost of both shirts and jeans after discount is $71

Step-by-step explanation:

Given as :

The number of shirts bought = 3

The number of pair of jeans bought = 2

The cost of each shirt before discount = $12

The cost of each pair of jeans before discount = $19

The discount on total cost = $3

Let The total cost paid = $A

<u>Now, According to question</u>

Total cost of items = number of shirts bought × cost of each shirt before discount +  number of pair of jeans bought × cost of each pair of jeans before discount

Or, A = 3 × $12 + 2 × $19

Or, A = $36 + $38

Or, A = $74

<u>Again</u>

Discount of $3 is applied on total cost

So, The cost of items after discount = $74 - $3

Or, The cost of items after discount = $71

Hence, The cost of both shirts and jeans after discount is $71 Answer

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3 years ago
What is a solution of -8x+5&gt;=11<br> A.-1/2<br> B.3<br> C.0.25<br> D.-1
Blababa [14]

Answer:

i got -2

Step-by-step explanation:

1 step; 8*x-5-(11)=0

2 step; 8x - 16  =   8 • (x - 2)

3 step;  Solve :    8   =  0

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final part  Add  2  to both sides of the equation :  

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3 years ago
Suppose the lead actor in a play is 5 feet, 9 inches tall. Convert his height to meters. Round your answer to the nearest hundre
Yanka [14]
Given that the lead actor is 5 feet 9 inches tall, converting this to meters we shall have:
1 ft = 0.3048 m
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1 in = 0.0254 m
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6 0
3 years ago
In one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the enti
jekas [21]

Answer:

X \sim Hyp (N = 810, M=102, n=4)

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

Step-by-step explanation:

For this case we can model the variable of interest with the hypergeometric distribution. And with the info given we can do this:

X \sim Hyp (N = 810, M=102, n=4)

P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}  

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes  

And for this case we want to find the probability that none of the scales selected would be defective so we want to find this:

P(X=0)

And using the probability mass function we got:

P(X=0) = \frac{(102C0)(810-102 C 4-0)}{810C4}  

And solving we got:

P(X=0)= \frac{(102C0) (708C4)}{810C4} = 0.583

So then for the problem given the probability that the entire bath will be accepted (none is defective among the 4) is 0.583

6 0
3 years ago
PLEASE HELP!!!
Lelu [443]

y = 3x - 2 is the answer!

y = mx + b

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⭐ Please consider brainliest! ⭐

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