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USPshnik [31]
4 years ago
13

A scientist is about to collect data to compute a 95% confidence interval, but he is unsure of what a 95% confidence interval re

ally means. Help him out by filling in the blanks. Before a sample is chosen, there is a 95% ______________ that the sample will produce an interval containing the true mean value. After a sample has been chosen, there is 95% ________________ that the interval produced by the sample will contain the true mean value.
a. probability/probability

b. confidence/confidence

c. confidence/probability

d. probability/chance

e. probability/confidence
Mathematics
1 answer:
Zarrin [17]4 years ago
6 0

Answer:

c. confidence/probability

Step-by-step explanation:

The margin of error of a confidence interval is:

M = T*s.

In which T is related to the confidence level and s is the standard deviation of the sample.

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Before the sample is chosen

We choose our confidence level, which will determine the value of T. So the first answer is confidence.

After the sample is chosen

We are 95% sure that the true mean is in the sample. So the second answer is probability.

So the correct answer is:

c. confidence/probability

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Question 16
anastassius [24]

Step-by-step explanation:

Distance between 2 towns 360 miles showed length 3 inches

1800 miles = ? inches

360 miles = 3 inches

1 miles = 3/360 inches

1800 miles = 3/360 × 1800

= 15 inches

3 0
3 years ago
Find an equation for the line that passes through the points (1. - 4) and (-5.4).
DIA [1.3K]

Answer:

y=-4/3x-8/3

Step-by-step explanation:

Use the slope formula y2-y1/x2-x1

Finding the slope, 4-(-4)/-5-1 = 8/-6 = -4/3

y=-4/3x + b

Substituting,

-4=-4/3+b

-12/3+4/3=b

b=-8/3

y=-4/3x-8/3

5 0
3 years ago
How to turn repeated decimals into fractions
Ainat [17]
1. Write down the decimal divided by 1
2. Multiply both top and bottom by 10
3. Simplify the fraction.
6 0
3 years ago
An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

b) The approximate probability that at least 9 carry the gene is:

P(x\geq9)=1-P(x\leq 8)\\\\\\

P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\

P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021

8 0
3 years ago
Simplify.
marin [14]

1/2+(3/8−1/8)^2

= 1/2+(2/8)^2

= 1/2+(1/4)^2

= 1/2 + 1/16

= 8/16 + 1/16

= 9/16

Answer

9/16

3 0
3 years ago
Read 2 more answers
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