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BigorU [14]
3 years ago
5

What is the length of segment AB?

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

length of segment AB is 13

OR

AB = 13

Step-by-step explanation:

Use the Pythagorean Theorem with c being the length of segment AB.

a^2 + b^2 = c^2

5^2 + 12^2 = c^2

169 = c ^2 (square root both sides to get c by itself)

13 = c

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Answer:

250

Step-by-step explanation:

85% · n = 212.5

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.85n = 212.5

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6 0
3 years ago
Determine whether f(x) = 5x+1/x and g(x)= x/ 5x+1 are inverse functions explain how you know. please explain in steps or worded
Len [333]

Hello from MrBillDoesMath!

Answer:

No


Discussion:

If the functions are inverses, then f(g(x)) = x  for appropriate x. Consider x = 1.

g(1) = 1/ (5(1) + 1) = 1/6

f(g(1)) = f (1/6) =  5(1/6) + 1/ (1/6) = 5/6 + 6 = 6 5/6   <> 1

Conclusion: f(g(1)) <> 1 so the functions are not inverses


Thank you,

MrB

7 0
3 years ago
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natita [175]

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3 0
3 years ago
3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0
Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0

Hence, Proved that \sf \frac{3}{m+4} - \frac{4}{m} = 6 is equivalent to \sf 6m^2+25m+16 = 0.

6 0
3 years ago
Read 2 more answers
Which equation shows y=34x−52y=34x−52 in standard form?
ladessa [460]
It would be A, most definitely. 
5 0
3 years ago
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