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Marat540 [252]
3 years ago
7

102=v-66 its addition and subtraction one step practice

Mathematics
1 answer:
yaroslaw [1]3 years ago
3 0

Answer:To subtract 7 from 102, you have to regroup. You subtract 2 from 100, and 2 from 7, so it is 100-5. 100-5 is 95. The answer is 95. If you don't understand, tell me in the comments. This is just one method of subtracting.

Step-by-step explanation:

You might be interested in
Determine a25
posledela
I believe it’s 16/21 but I’m not sure.

4 0
2 years ago
The gross domestic product (GDP) of a certain country, which measures the overall size of the economy in billions of dollars, ca
DiKsa [7]

Answer:

The estimated GDP in 2007 is 12782 billion dollars.

The estimated GDP in 2011 is 15010 billion dollars.

The estimated GDP in 2012 is 15567 billion dollars.

Step-by-step explanation:

Consider the provided function.

g(y) = 557y +8883

Where y = 10 corresponds to the year 2010.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2007.

If y = 10 corresponds to the year 2010 then y = 7 corresponds to the year 2007.

Substitute the value of y = 7 in the provided function.

g(y) = 557(7) +8883

g(y) = 3899+8883

g(y) = 12782

Hence, the estimated GDP in 2007 is 12782 billion dollars.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2011.

If y = 10 corresponds to the year 2010 then y = 11 corresponds to the year 2011.

Substitute the value of y = 11 in the provided function.

g(y) = 557(11) +8883

g(y) = 6127+8883

g(y) = 15010

Hence, the estimated GDP in 2011 is 15010 billion dollars.

Part (C) Estimate the GDP (to the nearest billion dollars) in 2012.

If y = 10 corresponds to the year 2010 then y = 12 corresponds to the year 2012.

Substitute the value of y = 12 in the provided function.

g(y) = 557(12) +8883

g(y) = 6684+8883

g(y) = 15567

Hence, the estimated GDP in 2012 is 15567 billion dollars.

4 0
3 years ago
A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco
Brut [27]

Answer:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

\bar X_{A}=48250 represent the mean of elementary teachers

\bar X_{B}=45630 represent the mean for secondary teachers

s_{A}=3900 represent the sample standard deviation for elementary teacher

s_{B}=5530 represent the sample standard deviation for secondary teachers

n_{A}=26 sample size selected

n_{B}=24 sample size selected  

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis:\mu_{A}-\mu_{B}\leq 0

Alternative hypothesis:\mu_{A}-\mu_{B}>0

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0
2 years ago
Can someone please help me with my math homework
Natali5045456 [20]
Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles

time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)

Marcus travels 78000(2)(square) +32500(2)
= 84500yards
=48 miles

time = distance/speed
time=48/45
time=1.07 (1 hour 7 mins) 


a)Josephine arrives first
b)she arrives earlier by 2 mins.





6 0
3 years ago
Describe the values of c for which the equation has no solution. explain your reasoning.
Lera25 [3.4K]

Answer:

c=|x-7|

Step-by-step explanation:

5 0
2 years ago
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