Answer:
the answer is 5 I think I hope
Answer:
question wrong
Step-by-step explanation:
2 same angles
Answer:
Step-by-step explanation:
Given (64 y Superscript 100 Baseline) Superscript one-half.
Let us write it into an equation.
Apply radical rule: ![\sqrt[n]{a}=a^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
and 
![\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cleft%2864%20y%5E%7B100%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%26%3D%5Csqrt%5B2%5D%7B64%20y%5E%7B100%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%20y%5E%7B50%7D%20y%5E%7B50%7D%7D%20%5C%5C%26%3D%5Csqrt%5B2%5D%7B8%5E%7B2%7D%5Cleft%28y%5E%7B50%7D%5Cright%29%5E%7B2%7D%7D%20%5C%5C%26%3D8%20y%5E%7B50%7D%5Cend%7Baligned%7D)
Hence, is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.
For a definite answer, let us take a look at the given circle graph. You are given that landing on a blue sector will give 3 points, landing on a yellow sector will give 1 point, purple sector will give 0 points and red sector will give -1 point. You are asked to find the probability of landing -1, 0, 1 and 3 points. There are a total of 7 pie graphs in the circle.
For -1 point, you know that only a red sector will give you a negative one point. In the circle graph, there are two red portions. So you will have a probability of 2/7.
For the 0 point, you know that only a purple sector will give you zero point. In the circle graph, there are two purple portions. So you will have a probability of 2/7.
For the 1 point, you know that only a yellow sector will give you one point. In the circle graph, there are two yellow portions. So you will have a probability of 2/7.
For the 3 points, you know that only a blue sector will give you three points. In the circle graph, only one blue portion is shown. So you will have a probability of 1/7.
