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Studentka2010 [4]
3 years ago
10

If the area of Ohio remains the same, but had the same population density as Alaska , how many people would we expect to live in

Ohio? Express your answer rounded to the nearest tenth of a million.
Mathematics
2 answers:
sdas [7]3 years ago
5 0
<span>The population density of Alaska, per 2010 Census Bureau data, is 1.2 people per square mile. The land area of Ohio is known to be 44,825 square miles. If we then multiply these two figures, we would see the population of Ohio to only be 53,790 people, or 0.053 million. Rounding (up significantly) to the nearest tenth of a million, that would only be 0.1 million people.</span>
elixir [45]3 years ago
3 0
Remember that population density Pd= \frac{population}{area}.
First, lets calculate the population density of Alaska. IAs of 2016 the population of Alaska is 741894, and its area is 663268 sq mi; therefore, Pd= \frac{741894}{663268}= 1.12/sq mi.
Now, the area of Ohio is <span>44825 sq mi.
Second, lets replace the population density of Alaska and the Area of Ohio into our population density equation to get the new expected population of Ohio:
</span>1.12= \frac{population}{44825}
population=(1.12)(44825)
population=50204

We can conclude that if Ohio had the same density population of Alaska, 50204 persons would live in Ohio. 
<span>
</span>
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Please help me with this.
vodka [1.7K]

The rate of change would be 300 bacteria per minute at 0.1 minutes past 1 PM

<h3>The exponential function of the bacteria</h3>

The given parameters are:

Initial, a = 20

At 30 minutes, Value = 500

An exponential function is represented as:

y = ab^t

Where a is the initial value.

So, we have:

y = 20b^t

After 30 minutes, we have:

20b^30 = 500

Divide both sides by 20

b^30 = 25

Take the 30th root of both sides

b = 1.11

Substitute b = 1.11 in y = 20b^t

y = 20(1.11)^t

Hence, the exponential model is y = 20(1.11)^t

<h3>Minutes to reach 11,000</h3>

This means that:

y = 11,000

So, we have:

20(1.11)^t = 11000

Divide both sides by 20

1.11^t = 550

Take the logarithm of both sides

tlog(1.1) = log(550)

Divide both sides by log(1.1)

t = 66

Hence, the population would reach 11,000 after 66 minutes

<h3>The population at 2PM</h3>

This means that:

t = 60 i.e. 60 minutes after 1PM

So, we have:

y = 20(1.11)^60

Evaluate

y = 10481

Hence, the population at 2PM is 10481

<h3>The rate of change at 2PM</h3>

In (c), we have:

y = 10481 ------ population at 2PM is 10481

t = 60

The rate of change is calculated as:

Rate = 10481/60

Evaluate

Rate = 174.68

Hence, the rate of change at 2PM is 174.68 bacteria per minute.

<h3>When the rate would be 300 bacteria per minute?</h3>

The rate of change is calculated as:

Rate = Population/Time

So, we have:

y/t = 300

This gives

y = 300t

Substitute y = 300t in y = 20(1.11)^t

300t = 20(1.11)^t

Divide both sides by 20

15t = (1.11)^t

Using a graphing calculator, we have:

t = 0.1

Hence, the rate would be 300 bacteria per minute at 0.1 minutes past 1 PM

Read more about exponential functions at:

brainly.com/question/11464095

#SPJ1

7 0
2 years ago
The cities D, E, and F lie, in respective order, approximately in a straight line. The distance from city D to city E is 125 mil
mamaluj [8]

Answer:

  35 miles

Step-by-step explanation:

The segment addition theorem tells you ...

  DE + EF = DF

  125 + EF = 160

  EF = 35 . . . . . . . subtract 125

The distance from E to F is about 35 miles.

5 0
3 years ago
if alisson worked the times in the table and makes $9.32 an hour, how much was her gross pay this week
LenaWriter [7]
Hrs worked = 9.25 + 8.75 + 9 + 8.25 + 9 = 44.25 hrs. (44.25 - 40 = 4.25 hrs overtime) 
<span>40 hrs * $9.32 = $372.80 (Straight time) </span>

<span>$9.32 * 1.5 = $13.98 (Overtime rate) </span>
<span>4.25 (Overtime hrs.) x $13.98 (Overtime rate) = $59.42 (Overtime pay) </span>

<span>$372.80 + $59.42 = $432.22 (Total gross pay)</span>
4 0
3 years ago
What is the equation of the line? (-2,-3) and (1,-3)
Wewaii [24]

Answer:

y=3

Step-by-step explanation:

3 0
3 years ago
Ying Zyiyu covered the first 300 miles of a trip going at 60 mph and the last hundred going at 40 mph. What was his average spee
Tomtit [17]

Answer:

53.33mph

Step-by-step explanation:

Let's calculated the total time spent on the journey first;

For the first 300miles the time spent is ;

From Distance = speed× time

time = Distance/ speed

= 300/60 = 5 hours

Similarly for the last 100mile the time taken is ;

100/40 = 2.5 hours

Total time spent = 5 +2.5 = 7.5 hours

Total distance covered 400miles

Therefore average speed = 400/7.5 =53.33mph

8 0
3 years ago
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