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3 years ago

Who was the first rapper to win a Grammy?

Geography

2 answers:

Natali [406]3 years ago

7 0

The first award for Best Rap Performance was presented to DJ Jazzy Jeff & The Fresh Prince

Rom4ik [11]3 years ago

4 0

Answer:

The answer is DJ Jazzy Jeff & The Fresh Prince. Hope it helps!

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Fine-grained clastic rocks are ______. Multiple choice question. easily eroded eroded with difficulty eroded with drastically di

AnnZ [28]

A property of fine-grained clastic rocks is that they are easily eroded.

<h3>Why are these rocks easily eroded?</h3>

Fine-grained clastic rocks have small fragments and grains which make them lighter than other rocks.

As a result they are more susceptible to weathering which then allows them to be easily carried off by water or air.

In conclusion, option A is correct.

Find out more on weathering at brainly.com/question/12734041.

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2 years ago

What is the prime characteristic that geologists use to separate minerals into classes?

sladkih [1.3K]

A mineral is a naturally occurring,inorganic, crystalline substance that aggregate to form rocks. Geologists separate minerals into classes based on their chemical composition. The different classes of minerals include halides, oxides, phosphates and sillicates. Rocks are usually classified based on the grouping and composition of minerals in rocks.

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3 years ago

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irga5000 [103]

Answer:

software

Explanation:

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2 years ago

Why do foreign investors hesitate to invest in Central America? lack of worthy projects

Inessa05 [86]

I believe its lack of worthy projects, but ill tell you if im wrong.

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3 years ago

Read 2 more answers

Find an equation for the perpendicular bisector of the line segment whose endpoints

zzz [600]

Answer:

y= -7/2x-26/2 or y= -7/2x-13

Explanation:

To solve this question you need all of these formulas:

gradient: $\frac{y2-y1}{x2-x1}$ , Point-Slope $y-y1=m(x-x1)$ ,

perpendicular m $(m1)x(m2)=-1$ , Midpoint $(\frac{x1+x2}{2}$ , $\frac{y1+y2}{2} )$

and equation of a line $y=mx+c$

where m stands for gradient

First things first.

To start you have to know the data of the line that includes the two endpoints, so you calculate its gradient (m) of this line with the gradient fromula: $m=\frac{-4-(-8)}{5-(-9)}$ , which equals 4/14 or 2/7

(It can also be called rise/run) (Remember the rule of signs where - and - equal +)

with that information you can proceed with the point-slope or point-gradient formula, so you plug the values: y-(-8) = 2/7 (x-(-9)), which results in y+8=2/7(x+9) and then y+8=2/7x+18/7.

To finish the equation you move eight to the other side. To simplify things you can change it into a fraction as I did, and remember to change signs.

y=2/7x+18/7 -8 -> y=2/7x+18/7-56/7 . This gives us the number of y=2/7x-38/7, which is the equation of the first line.

Now to know the gradient of the second line you apply the formula of perpendicular bisector where m1 x m2 = -1. We know m1 (gradient of the first line) is 2/7, so m2 = $\frac{-1}{2/7}$ = -7/2. m2 is therefore -7/2

Now you have to know the midpoint between the two endpoints, which will act as the start point of the perpendicular bisector

M (midpoint) = $(\frac{-9+5}{2} ,$ $\frac{8+(-4)}{2} )$ , which give us the coordinates of (-2, -6)

(remember, x coordinate is always first)

with this point we can apply again the point-slope formula to know the equation of the line:

y-(-6)=-7/2(x-(-2)) -> y+6=-7/2(x+2) -> y+6=-7/2x - 14/2

Move the 6 to isolate the y

y=-7/2x -14/2 - 12/2

which equals y= -7/2x -26/2

You can check the results in this page: GraphPlotter

https://www.transum.org/Maths/Activity/Graph/Desmos.asp

To make sure the answer is correct.

Hope it helps :)

8 0

2 years ago