For the answer to the question above, let's start with the whole circle.
Let's assume that <span>the maximum possible area of a rectangle inscribed in a complete circle is achieved when the rectangle is a square.
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D= Circle's Diameter = 16
square's area = (D^2) / 2 = 256/2 =128
Imagine we want to break the circle into two semicircles, the square would be divided into two rectangles which would have the maximum possible area.
rectangle's area = square's area / 2 = 128/2 = 64
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The stronger contrast in value between an object and the background, the more visual weight the object has. the stronger the contrast in value between an object and the background, the more visual weight the object has. dark values appear heavier than light values.