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2 years ago

Match the verbal expression with its algebraic expression.

Mathematics

1 answer:

Alex73 [517]2 years ago

3 0

Step-by-step explanation:

1. b + 2

2. x - 2

3. 2z

4. a ÷ 2

5. y^2

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For ΔABC, which two relationships are true?

Phoenix [80]

The two correct relationships are:

$cos(\theta)=\frac{AB}{AC} = sin(90-\theta)\\\\sin(\theta)=\frac{BC}{AC} = cos(90-\theta)$

<h3>What is a right-angled triangle?</h3>

The triangle shown is a right-angled triangle

Considering < $(90-\theta)^o$

$cos(90-\theta)=\frac{BC}{AC} \\\\sin(90-\theta)=\frac{AB}{AC}\\\\tan(90-\theta)=\frac{AB}{BC}$

Considering < $\theta$

$cos(\theta)=\frac{AB}{AC} \\\\sin\theta)=\frac{BC}{AC}\\\\tan(\theta)=\frac{BC}{AB}$

Comparing < $\theta$ and < $(90-\theta)^o$ , the true statements are:

$cos(\theta)=\frac{AB}{AC} = sin(90-\theta)\\\\sin(\theta)=\frac{BC}{AC} = cos(90-\theta)$

Learn more on trigonometry here: brainly.com/question/20519838

6 0

2 years ago

You are walking away from home at a constant velocity of 5 km per hour. The first landmark you see is your favorite fountain whi

Reptile [31]

R=5km
D=2km

T=D/R

T=2km/5km

4 0

3 years ago

An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airp

balu736 [363]

Answer:

r = 225 Mil/h speed of the airplane in still air

Step-by-step explanation:

Then:

d is traveled distance and r the speed of the airplane in still air

so the first equation is for a 4 hours trip

as d = v*t

d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)

Second equation the trip back in 5 hours

d = 5 * ( r - 25 ) (2)

So we got a system of two equation and two unknown variables d and

We solve it by subtitution

from equation (1) d = 4r + 100

plugging in equation 2

4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h

And distance is :

d = 4*r + 100 ⇒ d = 4 * ( 225) + 100

d = 900 + 100

d = 1000 miles

6 0

3 years ago

Someone help 6th grade math i will give brainliest

Soloha48 [4]

The first one is 64. The second one is -64. Third is 10000

8 0

3 years ago

Read 2 more answers

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers