If the restaurant uses 150 grams and then sells 50 sub sandwiches
The ham needed is 50 x 150 = 7500 gram = 7.5 kg
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Given :
Challenge given is to volunteer for about 1 1/2 hours per week .
Autum did at a rate of 6 3/4 hours per week .
To Find :
The comparison ( ratio ) her volunteers rate with the challenge rate .
Solution :
Simplifying challenge rate in in normal fraction ,
.
Also , simplifying her rate ,
.
Now , ratio of his work by challenge is :

Therefore , the ratio is 9/2 or 4 1/2 .
Hence , this is the required solution .
A decagram is 10 grams, so first lets convert the decagrams to grams and then after we'll change to kilograms.
If 1 decagram equals 10 grams, then 2500 decagrams is equal to:
2500*10 = 25000 grams
Now, 1 kilogram equals 1000 grams so 25000 grams equals:
25000/1000 = 25 kg
therefore, 2500 decagrams equals 25 kg