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blondinia [14]
3 years ago
14

The historical walking tour of a town covers a total distance of 5 miles. The map shows that the path of the tour travels 3 inch

es north, 4 inches east, 2 inches south, and 1 inch west. How many miles does each inch on the map represent?
Mathematics
2 answers:
lyudmila [28]3 years ago
8 0

Answer:

0.5 or B

Step-by-step explanation:

A little birdy told me so

stay safe

<3

kari74 [83]3 years ago
7 0
Since the problem is given all the total walking distance, the first thing we are going to do is find the total distance in the map:
Diastance_{map}=3+4+2+1
Distance_{map}=10
Now that we have the distance in the map, we can establish a ratio between the walking distance and the distance in the map:
\frac{5miles}{10inches} = 0.5 \frac{mile}{inch}

We can conclude that each inch the map represents 0.5 miles of walking distance. 

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A restaurant uses 150 grams of ham on each sub sandwich that it sells. If the restaurant sells 50 sub sandwiches, how much ham w
Morgarella [4.7K]

If the restaurant uses 150 grams and then sells 50 sub sandwiches

The ham needed is 50 x 150 = 7500 gram = 7.5 kg

8 0
1 year ago
Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report
Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M±\frac{t*s}{\sqrt{N}} where

  • M is the average track length (12 μm) in the report
  • t is the two tailed t-score in 99% confidence interval (2.977)
  • s is the standard deviation of track lengths in the report (2 μm)
  • N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12±\frac{2.977*2}{\sqrt{15}} =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0
3 years ago
Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a
Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio )  her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , 1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2} .

Also , simplifying her rate , 6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4} .

Now , ratio of his work by challenge is :

R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0
3 years ago
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shusha [124]

Answer:

,

Step-by-step explanation:

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3 years ago
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Tasya [4]
A decagram is 10 grams, so first lets convert the decagrams to grams and then after we'll change to kilograms.
If 1 decagram equals 10 grams, then 2500 decagrams is equal to:
2500*10 = 25000 grams
Now, 1 kilogram equals 1000 grams so 25000 grams equals:
25000/1000 = 25 kg
therefore, 2500 decagrams equals 25 kg
3 0
3 years ago
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