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Mariana [72]
3 years ago
14

Bored.... freeupvote ( and really easy) what is 174 divided by 5 -_-

Mathematics
1 answer:
padilas [110]3 years ago
3 0
The number 5 goes into the amount 174 exactly 34.8 times :)
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Encuentra la pendiente de la recta formada por los puntos A( 3 , -2 ) Y B( -5 , 3 )
QveST [7]

Answer:

\frac{5}{-8} or -0.625

Step-by-step explanation:

The slope formula is as shown:

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1}}

We can have A = (x_{1},y_{1}) and B = (x_{2},y_{2}).

We can hence plug in the values into the formula to get m=\frac{3-(-2)}{-5-3}.

As we simplify, the negatives on the top row cancel out to give us an addition sign instead and we add them.

m=\frac{5}{-8}

Brainliest would be appreciated!

3 0
3 years ago
Assigned newbits with the opposite values of oldbits if flipbits is true. ex: if oldbits = [1, 1, 0, 1] and flipbits is 1, then
Kisachek [45]

Franck's answer is better (using ~), but I just wanted to point out that the conditional in yours is slightly redundant. It's easy to forget that, since you already have a boolean value, you don't need to perform a comparison in your conditional. So you could have just done this...

<span>if x x = false; else x = true; <span>end</span></span>
5 0
3 years ago
Equation where c represent spot per number of parking spot per lot<br> 77c=1442
Liula [17]

Answer:

You would divide 1442 by 77 Giving you C=18.7

Hope this helped ^^

If not sorry ¯\_(ツ)_/¯

8 0
3 years ago
Read 2 more answers
Help quick please give an explanation too.
Lady_Fox [76]

Answer: (x+2)*(x-4)*(x+21) = 0 has "many" solutions

Step-by-step explanation: (x+2) = 0 only has one solution.  

(x+2)*(x-4) = 0 has two solutions, -2 and 4

(x+2)*(x-4)*(x+21) = 0 has three solutions, -2, 4, and -21, etc

If "many" means more than three, then add another (x+XX) term.  A quadratic equation generally has two solutions.

4 0
3 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
4 years ago
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