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Strike441 [17]
2 years ago
7

Identify the parameters p and n in the following binomial distribution scenario. Jack, a bowler, has a 0.38 probability of throw

ing a strike and a 0.62 probability of not throwing a strike. If Jack bowls 20 times, he wants to know the probability that he throws more than 10 strikes. (Consider a strike a success in the binomial distribution.)
Mathematics
1 answer:
Elanso [62]2 years ago
8 0

Answer:

p = 0.38, n = 20

The probability that he throws more than 10 strikes = 0.09233

Step-by-step explanation:

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of times Jack wants to bowl = 20

x = Number of successes required = number of strikes he intends to get

p = probability of success = probability that Jack throws a strike = 0.38

q = probability of failure = probability that Jack doesn't throw a strike = 0.62

P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)

P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)

P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)

P(X > 10) = 0.09233

There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.

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Step-by-step explanation:

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2 years ago
Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

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3 years ago
I don’t know how to answer my this math question, it’s easy so please help
Fofino [41]

which one ?

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3 years ago
One of the giraffes, Bernard, is sick. Last week he weighed 2,490 pounds. This week he weighs 2,312 pounds. If w represents the
victus00 [196]

Answer:

w+2,312=2,490

w=178\ pounds

Step-by-step explanation:

Let

w ----> the amount of weight lost in pounds

we know that

The amount of weight Bernard lost plus the weight of this week must be equal to the weight of the last week

so

The linear equation that represent this situation is

w+2,312=2,490

solve for w

subtract 2,312 both sides

w=2,490- 2,312=178\ pounds

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2 years ago
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