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hoa [83]
3 years ago
7

For the trapezoid ABCD E and F are the midpoints of

Mathematics
1 answer:
lawyer [7]3 years ago
6 0

Answer:

EF=\frac{b+d}{2}\ units

Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u>. states that the length of the mid-segment is equal to the sum of the base lengths divided by two.

so

EF=\frac{BC+AD}{2}

we have

BC=b\ units\\AD=d\ units

substitute the given values

EF=\frac{b+d}{2}\ units

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1) 3n+1=16-2n - add 2n to both sides - you should now be left with 5n+1=16 (remember the 2n gets canceled out) - subtract 1 from both sides - you should now be left with 5n=15 - now you divide by 5 to get n by itself - 15 divided by 5 is 3 - n=3 2) substitute n with 3 in to the original equation - so 3n+1=16-2n now becomes 3(5)+1=16-2(3) - you should get 10 for both so 10=10 3) according to the segment addition postualte , XR + YR = XY. - add 10+10 which stands for the lengths of XR and YR Answer - XY = 20
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