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Brrunno [24]
3 years ago
12

The neurotransmitter acetylcholine has the molecular formula of C7NH16O2+. If you wanted to make a 100mL solution of 10mM, how m

any grams of acetylcholine do you need to weigh?
Biology
1 answer:
podryga [215]3 years ago
7 0

Answer:

0.146 g

Explanation:

Given data:

Volume of solution = 100 mL

Molarity = 10 mM

Molecular formula = C₇NH₁₆O₂

Mass of  C₇NH₁₆O₂ needed = ?

Solution:

First of all we will convert the mM into M and mL to litter.

Volume of solution = 100 mL

Volume of solution = 100 / 1000 = 0. 1 L

Molarity = 10 mM

Molarity = 10 / 1000 = 0.01 M

Molar mass of  C₇NH₁₆O₂ = 146.21 g/mol

For 1M solution we dissolve 146.21 g/mol in one litter

For 0.01 M

146.21 g/mol × 0.01 mol/ L = 1.4624 g/L

while we have to make 0.1 L solution,

1.4624 g/L ×0.1 L = 0.146 g

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Phenylketonuria (PKU) is a recessive human disorder in which an individual cannot appropriately metabolize the amino acid phenyl
lutik1710 [3]

Answer

b. Regulate the diet of the affected persons to severely limit the uptake of the amino acid.

Explanation:

<u>This is the effective way of  managing PKU, if diet is not regulated, the blood plasma  Phenylketonuria levels continue to build up  from usual protein consumption. This leads to toxicity of the brain  and brain  dysfunctions. Nausea constipation, fatigues, health headaches are some of the results of the build up</u>.

Therefore to reduce the blood build up of phenylalanine and thus PKU;  Special diet  formulas rich in essential amino acids, and other needed nutrients which may be absent  in phenylalanine low diet  should be  adopted. Amino acids substitutes notably Tyrosine which  is lacking  from  failure of  phenyalanine breakdown in  phenylketouria is heavily  supplemented. Tyrosine is   important  in brain function for alertness, focus,nervous communication.

The  adoption of protein substitutes diet or regulated amino acid diet  is very important because , all the needed amino acid are available , thus protein catabolisms  which may  trigger phenylalanine build up  from muscles and liver storage withdrawal   is prevented thus  stabilizing its blood concentration.

8 0
3 years ago
An AAbb strain is crossed to an aaBB strain and the resulting progeny self-crossed. If A andB are located 10 cM apart from each
skelet666 [1.2K]

Answer:

20.3%

Explanation:

Given that:

An AAbb strain is crossed to an aaBB strain

i.e.

                   AAbb      ×      aaBB

gametes       Ab                   aB

For F₁

generation;  

If the resulting progeny are now self-crossed.

We know that the genetic distance between these two genes on the same chromosome is said to be 10 cM.

i.e. the recombinant gene = 10%; Hence, the parental gene will be (100 - 10)% = 90%

Ab ×   aB  =   Aa    AB      ab     Bb

From above; the parental gene;

Ab and   aB = 90% with each being 45%

i.e. Ab = 45%   and aB = 45%

while the recombinants genes are:

AB and ab = 10%

i.e. AB = 5%  and ab = 5%

Finally; the percentage of aaBB is = aB% ×  aB% × 100%

the percentage of aaBB is = 0.45 × 0.45 × 100%

the percentage of aaBB is = 20.25%  ≅ 20.3%

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