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Flura [38]
3 years ago
14

The owner of a snow cone shop used 1/4 of a gallon of syrup to make 16 snow cones. She used the same amount of syrup in each sno

w cone. How many gallons of syrup did she use to make each snow cone?
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

.015625

Step-by-step explanation:

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Sam and his family go out to eat for his birthday. The total bill is $123.79. If his dad leaves the waitress a 15% tip, how much
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Step-by-step explanation:

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Suppose a subdivision on the southwest side of Denver, Colorado, contains 1,400 houses. The subdivision was built in 1983. A sam
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Answer:

3.22% probability that the sample average is greater than $228,500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 227000, \sigma = 8500, n = 110, s = \frac{8500}{\sqrt{110}} = 810.44

What is the probability that the sample average is greater than $228,500?

This is 1 subtracted by the pvalue of Z when X = 228500. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{228500 - 227000}{810.44}

Z = 1.85

Z = 1.85 has a pvalue of 0.9678

1 - 0.9678 = 0.0322

3.22% probability that the sample average is greater than $228,500

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