7v = 2v - 20
First, subtract 2v from both sides. / Your problem should look like: 7v - 2v = -20
Second, simplify 7v - 2v to 5v. / Your problem should look like: 5v = -20
Third, divide both sides by 5. / Your problem should look like: v =
Fourth, simplify
to 4. / Your problem should look like: v = -4
Answer:
v = -4
Answer: THE ANSWER IS D. Yes; no value in the domain corresponds to more than one value in the range.
Find the domain and range.
Domain:
{
−
2
, 3
, −
0.5
, 4
}
Range:
{
9
}
Step-by-step explanation: ITS NOT A OR C
Determine if the relation is a function.
The relation is a function.
Q equals cube root of 64, because if q to the power of 3 is 64, then you need to cube root 64 to just get q
Answer:
-9/11
Step-by-step explanation:
slope is change in y/change in x
change in y is 9 (12-3)
change in x is -11 (-17--8)
slope is -9/11
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
