2 years ago

Which type of bacteria is a common cause of gastrointestinal infections?

SAT

1 answer:

inna [77]2 years ago

6 0

Your answer will be escherichia coli

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babymother [125]

Answer:

$P(x = 3) = 0.1700$

Explanation:

Given

$n = 15$

$p = 0.3$

Required

Determine P(x = 3)

This is calculated using:

$P(x) = ^nC_xp^x(1-p)^{n-x}$

So, we have:

$P(x = 3) = ^{15}C_3*0.3^3*(1-0.3)^{15-3}$

$P(x = 3) = ^{15}C_3*0.3^3*(1-0.3)^{12}$

$P(x = 3) = 455 *0.027*(0.7)^{12}$

$P(x = 3) = 455 *0.027*0.0138412872$

$P(x = 3) = 0.17004021325$

$P(x = 3) = 0.1700$

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