Like XZ divides the cord YV into two congruent parts (YW=5.27 cm=WV), this segment XZ must be perpendicular to the segment YV, then the angle XWY in triangle XWY is a right angle (90°) and the triangle XWY is a right angle.
We can apply the trigonometric ratios in triangle XWY:
Hypotenure: XY
sin 44°=(Opposite leg to 44°)/(hypothenuse)
sin 44°=YW/XY
sin 44°=(5.27 cm)/XY
Solving for XY. Cross multiplication:
sin44° XY=5.27 cm
Dividing both sides of the equation by sin 44°:
sin 44° XY / sin 44° = (5.27 cm)/sin 44°
XY=(5.27/sin 44°) cm
XY=(5.27/0.694658370) cm
XY=7.586462929 cm
This value XY is the radius of the circle, then:
XZ=XY→XZ=7.586462969 cm
tan 44°=(Opposite leg to 44°) / (Adjacent leg to 44°)
tan 44°=YW/XW
tan 44°=(5.27 cm)/XW
Solving for XW. Cross multiplication:
tan 44° XW=5.27 cm
Dividing both sides of the equation by tan 44°:
tan 44° XW / tan 44°=(5.27 cm)/tan 44°
XW=(5.27/tan 44°) cm
XW=(5.27/0.965688775) cm
XW=5.457244753 cm
WZ=XZ-XW
WZ=7.586462969 cm-5.457244753 cm
WZ=2.129218216 cm
Rounded to 2 decimal places:
WZ=2.13 cm
Answer: The <span>measurement is closest to the measure of segment WZ is
2.13 cm</span>
Answer:
The Division Property of Equality
Step-by-step explanation:
<u>The Addition Property of Equality:</u> When you add something to one side of the equation, you must add the same thing to the other side.
<u>The Subtraction Property of Equality:</u> When you subtract something from one side of the equation, you must subtract the same thing from the other side.
<u>The Multiplication Property of Equality:</u> When you multiply something to one side of the equation, you must multiply the same thing to the other side.
<u>The Division Property of Equality:</u> When you divide something from one side of the equation, you must divide the same thing from the other side.
In this case, you have to divide both sides of the equation by 5 to get x = 4. That means that the division property of equality was used.
I hope this helps! Have a great day!
Step-by-step explanation:
1)The given equations are:
x − 2y = 6 ...(i)
3x − 6y = 0 ...(ii)
Putting x = 0 in equation (i) we get
=> 0 - 2y = 6
=> y = -3
x = 0, y = -3
Putting y = 0 in equation (i) we get
⇒x-2×0=6
⇒x=6
x = 6, y = 0
Use the following table to draw the graph
x 0 6
y -3 0
Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn
Graph of the equation ..(ii)
3x - 6y = 0 ...(ii)
Putting x = 0 in equation (ii) we get
⇒3×0-6y=0
=> y = 0
x = 0, y = 0
Putting x = 2 in equation (2) we get
⇒3×2-6y=0
=> y = 1
x = 2, y = 1
Use the following table to draw the graph.
x 0 2
y 0 1
Draw the graph by plotting the two points O(0,0) and D(2,1) from table
We see that the two lines are parallel, so they won’t intersect
Hence there is no solution
2)
Answer:
AB and EF
Step-by-step explanation:
They are the same length
