Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
I think the first numerator cant be Z so I solved the question assuming it is 2;
Answer:
(x,y,z)=(1,5,7)
Hope this helps.
January . . . $57.85
March . . . . 4 times as much = 4 (57.85) = $231.40
Deposit 78.45 more . . . ($231.40 + 78.45) = <em>$309.85</em> .
Notice that "interest" is never mentioned anywhere in this problem.
In other words, it doesn't matter whether Julie's savings account is
in a bucket in the basement, a mayonnaise jar on the porch, under
her mattress, or in a bank that pays no interest.
Without interest, $309.85 is what she <em><u>does</u></em> have<em><u /></em> in November, which
is about right for savings accounts in banks these days.
What her balance <em><u>should</u></em> be in November is an entirely different subject.
Answer:
18x +9h
Step-by-step explanation:
Such problems are tedious, but not difficult. The trick is to avoid making mistakes in the algebra.
Answer:
Step-by-step explanation:
Instead of dividing both sides by 5, it is multiplied
5x + 3 = 6 {Subtract 3 from both sides}
5x + 3 - 3 = 6-3
5x = 3 {Divide both sides by 5}
5x/5 = 3/5
x = 3/5
