Answer:
The require gradient is 3/5
Step-by-step explanation:
y(x) = 5x/(2x^2+4).................(1)
y(sqrt(3)) = sqrt(3)/2 => (sqrt(3), sqrt(3)/2) is a point on the curve of (1)
differentiate y(x) with respect to x using the quotient rule to get
y'(x) = 20x^2/(2x^2+4)^2 ................(2)
substitute x = (sqrt(3), sqrt(3)/2) in (2)
y'(sqrt(3))
= 20(sqrt(3))^2 / (2(sqrt(3))^2 + 4)^2
= 20*3 / (10)^2
= 60 / 100
= 3/5
