Answer:
Step-by-step explanation:
All the masses here are based on the main mass of the sand. So we will call sand "x". If there is two times as much cement as sand, then cement is 2x; if there is three times as much stone as sand, then stone is 3x. All of these added together equal a mass of 600 kg:
x + 2x + 3x = 600 so
6x = 600 and
x = 100 kg
There are 100 kg of sand. That means that there is 200 kg of cement and 300 kg of stone
number is 3.8
subtract 4 from -15 then divide by five
Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
Answer:
387420489
Step-by-step explanation:
Answer:
for the seniors, the answer is $12, and for the children, the answer is 8.
Step-by-step explanation: