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MaRussiya [10]
3 years ago
15

The diameter of a circle is 15in. Find the circumference to the nearest tenth (urgent)

Mathematics
2 answers:
givi [52]3 years ago
7 0

Answer:

I believe it is 47.1

ivann1987 [24]3 years ago
3 0

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>47</em><em> </em><em>inches</em><em>. </em>

<em>Answer</em><em> </em><em>is</em><em> </em><em>rounded</em><em> </em><em>to the nearest tenth place</em><em>. </em>

Step-by-step explanation:

given \: that \:  \\ diameter \: of \: circle \:  = 15 \: in \\ we \: know \: that \: \\  circumference \: of \: circle \:  = d\pi \\ on \: substitutig \: d \:  = 15 \: in \:  \\ in \: the \: formula \: we \: get \\ circumference \: of \: circle \:  = 15\pi \\ substitute \: \pi = 3.14 \\  = 5 \times 3.14 \\  = 47.123 \\ when \: the \: answer \: is \: rounded \: to \ \\  the \: nearest \:  tenth \: we \: \\  get \: 47 \: in \: as \: the \: answer.

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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3 years ago
For the following amount at the given interest rate compounded​ continuously, find​ (a) the future value after 9 ​years, (b) the
Stella [2.4K]

Answer:

(a) The future value after 9 ​years is $7142.49.

(b) The effective rate is r_E=4.759 \:{\%}.

(c) The time to reach ​$13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of P dollars is invested at a rate of interest r compounded continuously for t years, the compound amount is

A=Pe^{rt}

(a) From the information given

P=4700

r=4.65\%=\frac{4.65}{100} =0.0465

t=9 \:years

Applying the above formula we get that

A=4700e^{0.0465\cdot 9}\\A=7142.49

The future value after 9 ​years is $7142.49.

(b) The effective rate is given by

r_E=e^r-1

Therefore,

r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}

(c) To find the time to reach ​$13,000, we must solve the equation

13000=4700e^{0.0465\cdot t}

4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88

3 0
3 years ago
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2. (5/3y) + 2y - 12
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3. ?

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4 0
2 years ago
What is 0.362 in decimal expanded form
FromTheMoon [43]
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8 0
3 years ago
The expressions 10/12(245b−365) and 2/3(3b+6) represent the lengths of the diagonals of parallelogram WXYZ. For what value of b
makkiz [27]

Answer:

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Step-by-step explanation:

Length of diagonals of a parallelogram = \frac{10}{12}(245b - 365) and \frac{2}{3}(3b+6)

If the given parallelogram is a rectangle,

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1225b - 12b = 24 + 1825

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b = \frac{1849}{1213}

b = 1.52

5 0
3 years ago
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