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Crazy boy [7]
2 years ago
14

Is 5/8 an irrational number.?

Mathematics
2 answers:
Nikitich [7]2 years ago
4 0

Step-by-step explanation:

yes it is . becoz if you kbow the 5 is to 8 means it is an irrational number

BlackZzzverrR [31]2 years ago
3 0

Answer:

no

Step-by-step explanation:

an irrational number is a number that can't be expressed in fraction

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What you get when you add numbers together
Yuki888 [10]
You get a "sum" when you add numbers together.
4 0
3 years ago
Plz helpppppppppppppppppppppppppppppppppppp quick
Tanzania [10]

Answer:

B. 8

Step-by-step explanation:

6, 15, 7, 5, 11, 11, 8

5, 6, 7, 8, 11, 11, 15

The middle number is 8.

4 0
3 years ago
Read 2 more answers
How many 30 are there in 600
strojnjashka [21]
The question that is asked is pretty straight forward. Only thing that needs to be found is the number of 30 in the number 600. By dividing 600 by 30 we can arrive at the desired result.
Number of 30 in 600 = 600/30
                                 = 60/3
                                 = 20
So there are 20 number of 30s in the number 600. This method can be used to find answers to several other similar kind of questions like the number of 10s in 1000.Following the same procedure we get
Number of 10 in 1000 = 1000/10
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5 0
2 years ago
Read 2 more answers
Find an expression which represents the difference when (9x−6) is subtracted from (6x+7) in simplest terms.
evablogger [386]

Answer:

3x + 1

Step-by-step explanation:

9x -6 -6x +7

9x-6x -6 +7

3x +1

8 0
2 years ago
Please help me!!!!!​ i need full answer.
salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( \frac{x+y}{2})sin (\frac{x-y}{2} )

sin x - sin y = 2cos (\frac{x+y}{2} )sin (\frac{x-y}{2} )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin(\frac{A+B}{2})sin(\frac{A-B}{2} ) ]² + [ 2cos(\frac{A+B}{2} )sin(\frac{A-B}{2} ) ]²

= 4sin² (\frac{A+B}{2} )sin² (\frac{A-B}{2} ) + 4cos² (\frac{A+B}{2} )sin² ( \frac{A-B}{2} )

= 4sin² (\frac{A-B}{2} )[ sin² ( \frac{A+B}{2} ) + cos² ( \frac{A+B}{2} ) ← sin²x + cos²x = 1

= 4sin² ( \frac{A-B}{2} ) × 1

= 4sin² ( \frac{A-B}{2} ) = right side ⇒ proven

4 0
3 years ago
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