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iragen [17]
3 years ago
12

Farmer fernanda wants to put a fence around her rectangle field . The length of the field is 40 feet less than 3 times the width

. If she has 320 feet of fencing, what are the dimensions of the field?
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

Length: 110 feet

Width: 50 feet

Step-by-step explanation:

we know that

The perimeter of rectangle is equal to

P=2(L+W)

where

L is the length of rectangle

W is the width of rectangle

we have

P=320\ ft

so

320=2(L+W) ----> equation A

L=3W-40 ----> equation B

Solve the system by substitution

substitute equation B in equation A

320=2(3W-40+W)

solve for W

320=2(4W-40)

320=8W-80

8W=320+80

8W=400

W=50\ ft

Find the value of L

L=3(50)-40=110\ ft

therefore

The dimensions of the field are

Length: 110 feet

Width: 50 feet

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Answer:

Maximum value: 3* \sqrt{n}

Minimum value: -3* \sqrt{n}

Step-by-step explanation:

Let g(x) = x_1^2 + x_2^2+x_3^2+ ----+ x_n^2 , the restriction function.The Lagrange Multiplier problem states that an extreme (x1, ..., xn) of f with the constraint g(x) = 9 has to follow the following rule:

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Note that the partial derivate of f respect to any variable is 1, and the partial derivate of g respect xi is 2xi, this means that

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Where c is a constant that doesnt depend on i. In other words, there exists c such that (x1, x2, ..., xn) = (c,c, ..., c). Now, since g(x1, ..., xn) = 9, we have that n * c² = 9, or

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When c is positive, f reaches a maximum, which is \frac{3}{\sqrt{n}}  +  \frac{3}{\sqrt{n}} +  \frac{3}{\sqrt{n}}  + ..... +  \frac{3}{\sqrt{n}}  = n *  \frac{3}{\sqrt{n}}  = 3 * \sqrt{n}

On the other hand, when c is negative, f reaches a minimum, -3 * \sqrt{n}

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4 0
3 years ago
Read 2 more answers
Solve plsssss i need help ASAP
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