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Olegator [25]
2 years ago
7

How do I determine if a limit exist considering how it looks on a graph? Can I determine if a limit exists solely from the graph

? Like can I determine if this limit exists solely from looking at the graph:

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer: See below

Step-by-step explanation:

1. At x=1, the limit does not exist. If you see an open circle on the graph like you do here, you know that the function is discontinuous. This graph actually shows a jump discontinuity at x=1.

2.  You can determine if a limit exists by solely looking at the graph. Unfortunately in this case, f(1)=1 and \lim_{x \to \ 1^-} f(x) are not equal to each other. Therefore, the limit does not exist.

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I got -64/3 for this problem.
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Simplificar as expressões<br><br> 7√32 - 5√2 + √8<br><br> 2√150 - 4√54 + 6√24
SIZIF [17.4K]
We try to represent each number inside the square root as a product of a square and another number.

a) 7√32 - 5√2 + √8

√32  = √(16 *2) = √16 * √2  = 4* √2 =  4√2

√8 = √(4 *2) = √4 * √2  = 2* √2 = 2√2

7√32 - 5√2 + √8 = 7*(4√2) - 5√2 + 2√2 =
      
                         = 28√2  - 5√2 + 2√2          Factorize out √2

                           = (28 - 5 + 2)√2  

                          =  25√2      

b)      2√150 - 4√54 + 6√24       

√150 = √(25 * 6) = √25 * √6 = 5*√6 = 5√6

√54 = √(9 * 6) = √9 * √6 = 3*√6 = 3√6

√24 = √(4 * 6) = √4 * √6 = 2*√6 = 2√6


2√150 - 4√54 + 6√24 = 2*(5√6) - 4*(3√6) + 6*(2√6)

                                = 2*5√6 - 4*3√6 + 6*2√6

                                = 10√6  - 12√6 + 12√6        Factorize √6

                               =  (10 - 12 + 12)√6

                               =  10√6
7 0
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Answer: 9.4

Step-by-step explanation:

if you see on the screenshot if you draw a line between the 2 it mesures 9.4

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