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labwork [276]
3 years ago
12

1. x+y=-3 ? What is the answer

Mathematics
2 answers:
stich3 [128]3 years ago
8 0

Answer:

x=-6 + y= 3

Step-by-step explanation:

noname [10]3 years ago
5 0

Answer:

x-intercept(s):  ( − 3 , 0 )

y-intercept(s):  ( 0 , − 3 )

Step-by-step explanation:

To find the x-intercept, substitute in  0  for  y  and solve for  x . To find the y-intercept, substitute in  0  for  x  and solve for  y

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Jason ate 1/2 of a whole pizza. The next day, he shared the remaining pizza between himself and 2 friends. What fraction of the
suter [353]

Answer:

1/6

Step-by-step explanation:

jason ate 1/2, so only 1/2 of the pizza is left.

1 ÷ 2 = 1/2

he split it equally between himself and 2 friends (3 people)

1/2 ÷ 3

= 1/2 × 1/3

=1/6

8 0
3 years ago
Help please
bearhunter [10]

Answer:

1. 7.66 x 10^4

2. 2.415×10²

Step-by-step explanation:

2. 8×105-5.7×105=241.5

4 0
3 years ago
How many 1/8-inch pieces of ribbon can be cut from a piece of ribbon that is 3/4 inch long? and I cant be a friction
Anarel [89]

Answer:

100 inches

Step-by-step explanation:

8 0
3 years ago
A university's freshman class has 10000 students. 2500 of those students are majoring in Engineering. What percentage of the fre
Musya8 [376]

Answer:

25%

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8 0
3 years ago
Read 2 more answers
Question 6
Firdavs [7]
So hmmmmm, notice... the boat went up in 3hrs, came back to the starting point in 2hrs, it went up 108km, it came back, well, from 108km to distance 0, so the distance on the way back is just the same 108km

now... let's say the stream has a speed rate of "r", and the boat has a still water speed rate of "b"

bear in mind that, when the boat is going UP, is not really going "b" fast, because the stream's "r" rate is going against it, and thus subtracting "r" from "b", so is really going " b - r " fast

when the boat is going down, is not going "b" fast either, because, again the stream's rate "r" is adding to it, because is going with the current, so is really going " b + r " fast

now, recall your d =rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&108&b-r&3\\
downstream&108&b+r&2
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
108=3(b-r)\implies \frac{108}{3}=b-r\\
\qquad 36=b-r\implies 36+r=\boxed{b}\\\\
108=2(b+r)\implies 54=b+r\\
\qquad 54=\boxed{36+r}+r
\end{cases}

solve for "r"

what's b?  well, 36+ r = b
7 0
4 years ago
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