Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Answer:
12 sales
Step-by-step explanation:
Let x represent the number of sales each man had.
For Salesman A, he earns $65 per sale; this is 65x.
For Salesman B, he earns $40 per sale; this is 40x. We also add to this his weekly salary of $300; this gives us 40x+300.
Since their pay was equal, set the two expressions equal:
65x = 40x+300
Subtract 40x from each side:
65x-40x = 40x+300-40x
25x = 300
Divide both sides by 25:
25x/25 = 300/25
x = 12
-2, -5, -8
You're subtracting three each time.
To round off to 10, the difference should range from 5 to 14. If the difference between two numbers is from 5 to 14, they all are rounded to 10.
Example:
(near to 10)



<h3>
Answer: 360</h3>
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Explanation:
We have 3 even values (2,4, and 6) so this is the number of choices we have for the units digit. Recall that a number is even if the units digit is 0,2,4,6 or 8.
Once we have the units digit selected, we have 6-1 = 5 choices for the first slot, 6-2 = 4 choices for the second slot, and so on until we get down to 6-5 = 1 choice for the fifth slot
We could write it out like this
- slot one = 5 choices
- slot two = 4 choices
- slot three = 3 choices
- slot four = 2 choices
- slot five = 1 choice
- slot six = units digit = 3 choices
Multiply those values out: 5*4*3*2*1*3 = 360
There are 360 different even numbers possible.