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skelet666 [1.2K]

4 years ago

12

Using the given points and line, determine the slope of the line. (-3,0) and (2,7)

2 answers:

o-na [289]4 years ago

3 0

Answer:

slope = $\frac{7}{5}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (2, 7)

m = $\frac{7-0}{2+3}$ = $\frac{7}{5}$

Finger [1]4 years ago

3 0

Hello!

<em>Hint: ⇒ Slope formula: ⇒ </em> $\frac{Y_2-Y_1}{X_2-X_1}$

$Y_2=7\\ Y_1=0\\\\X_2=2\\X_1=-3$

$\frac{7-0}{2-(-3)}=\frac{7}{5}$

$\boxed{\frac{7}{5}}\checkmark$

$\boxed{\frac{7}{5}}$ , which is our correct answer.

Hope this helps you!

Have a great day! :)

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The Miguel traces a circle with the radius of 25 cm like the one shown. He will color the shade section what is the area of the

Scilla [17]

Answer: The area of shaded section is 491.07 cm²

Step-by-step explanation:

Given: Radius of the circle = 25 cm

Now as shown in figure the shaded region is a quadrant.

Therefore the central angle is 90°

Now as we know

Area of sector is given by

$Area= \pi r^2 \dfrac{\theta}{360^\circ}$ where r is radius and $\theta$ is central angle

So we have

$Area = \dfrac{22}{7} \times (25)^2\times \dfrac{90^\circ}{360^\circ} \\\\\Rightarrow Area= \dfrac{22}{7} \times 625 \times \dfrac{1}{4} \\\\\Rightarrow Area= \dfrac{11}{7} \times 625 \times \dfrac{1}{2} = 491.07cm^2$

Hence, the area of shaded section is 491.07 cm²

5 0

4 years ago

Find the value of each variable. Lines that appear tangent are tangent, and the dot is the center. (Answer in the form a=? b=? c

Anni [7]

Answer:

a = 60°/2 = 30°

b = 84/2 = 42°

c = (100+60)/2 = 80°

d = 360-100-60-84 = 116°

Answered by GAUTHMATH

3 0

3 years ago

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Mrac [35]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

3 years ago

Order the following lost from least to greatest. |-65|, -19, 45, 21.7

makkiz [27]

Answer:

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3 0

3 years ago