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inessss [21]
4 years ago
15

Could someone please help me with this this is my first post and i really need help

Mathematics
1 answer:
valina [46]4 years ago
3 0
Yes it is d for sure and glad to see you on brainly!
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What does ‘j’ equal
IgorLugansk [536]

Answer:

J=-50

Step-by-step explanation:

6 0
4 years ago
17. Tonya's mother is 1.5 times as tall as
andrew-mc [135]

The question is incomplete:

17. Tonya's mother is 1.5 times as tall as  Tonya was when she was 6. How tall  is Tonya's mother? Use the correct  number of significant digits.

The image with the information about Tonya's height is attached.

Answer:

68 in.

Step-by-step explanation:

According to the information given, you can write the following expression:

x=1.5y

x=Tonya's mother height

y= Tony's height when she was 6

Also, you know from the table that Tonya's height when she was 6 was 45 in. and you can replace this value in the formula:

x=1.5*45

x=67.5

Because of this, the answer is that Tonya's mother height is 68 in.

3 0
3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
If I have 87 points and I want to get to 700, how many more points do I need?
garri49 [273]
Subtract 87 from 700
700 - 87 = 613
You need 613 more points
4 0
3 years ago
Read 2 more answers
Can someone help me please?!
Zanzabum

Answer:

its three good sir

Step-by-step explanation:

3 0
3 years ago
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