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4 years ago

6,000(1-(1+0.06)‐³²)/0.06(1+0.06)

Mathematics

2 answers:

irakobra [83]4 years ago

7 0

Woahhhhhh numbers

Step-by-step explanation:

I don’t know.

alekssr [168]4 years ago

6 0

Answer:

79716.98

Step-by-step explanation:

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A party planner is going to use an arch of balloons for a parade of recent graduates. The estimated curve the

lesya [120]

Answer:

Option (4)

Step-by-step explanation:

Party planner has used an arc of balloons for the parade.

This arc starts from x = 0 along the ground and f(x) defines the height of the arch.

From the table attached, it is clear that at x = 4 maximum height of the arch is 9.6 feet.

Therefore, clearance space below the arc is 9.6 feet which is greater than 9 feet, minimum height required for the clearance of the parade.

Option (4) will be the answer.

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3 years ago

Each package contains 4 identical bags of rice and a 7 pound bag of beans

Taya2010 [7]

Whats the question? I cant answer the question if there is no question.

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2 years ago

Use a(x) and b(x) shown below to evaluate the given expressions.

AnnZ [28]

Hello!

Let's begin with question 1, 2a(x) · b(x) = ?

2(3x - 1) · $2^{x}$

$2^{x}$ · (6x - 2)

Question 2, a(x) + 2b(x) = ?

3x - 1 + 2( $2^{x}$ )

Question 3, $\frac{b(x)}{2a(x)}$ = ?

$\frac{2^{x}}{2(3x - 1)}$

$\frac{2^{x}}{6x - 2}$

Question 4, 2a(x) + b(x) = ?

2(3x - 1) + $2^{x}$

6x - 2 + $2^{x}$

Question 5, a(x) - b(2x) = ?

3x - 1 - $2^{2x}$

3 0

3 years ago

Read 2 more answers

5000 jumps for 7 hours how many per hour

xenn [34]

Here is the formula.

5000j/7h = 714.285714j per 1 hour

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3 years ago

Read 2 more answers

write a variable expression to describe the rule of each progression then calculate the term 20 or 20 term1.) 6,12,18,24,...2.)3

Dmitriy789 [7]

1) 6, 12,18,24

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 6, d = 6

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 6 + 19}\times6 \\ T_{20\text{ }}\text{ = 6 + 114} \\ T_{20\text{ }}\text{ = 120} \end{gathered}$

2) 3,6,9,12

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 3, d = 3

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 3 + 19 }\times3 \\ T_{20\text{ }}\text{ = 3 + 57} \\ T_{20\text{ }}\text{ = 60} \end{gathered}$

3) 1,5,9,13

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 1, d = 4

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 1 + 19 }\times4 \\ T_{20\text{ }}\text{ = }1\text{ + 76} \\ T_{20\text{ }}\text{ = }77 \end{gathered}$

5 0

1 year ago

6,000(1-(1+0.06)‐³²)/0.06(1+0.06)​

6,000(1-(1+0.06)‐³²)/0.06(1+0.06)