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spayn [35]
3 years ago
11

Which of the following is a method used to prevent soil erosion? A. Tilling the soil / B. Contour farming / C. Adding worms to s

oil / D. Adding fertilizers to soil
Biology
2 answers:
lapo4ka [179]3 years ago
8 0

Answer: B. Contour farming

Explanation:

Contour farming is a sustainable practice of conserving the soil from erosion so as to retain it's fertility for the next harvest.  In this method plants are grown over the contours of the slopes at a slight elevation. This process allows the absorption of water by the soil and prevents the surface runoff. Hence, prevents the loss of soil fertility by soil erosion due to water.

skad [1K]3 years ago
5 0
I'd say
B. Contour Farming 
since it's planting on a flat surface and creating w/ridges to help prevent water from taking the crops away
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Would natural gas be considered a nonrenewable resource? who or why not?
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12.36Un balón lleno contiene 12 kg de oxígeno, O2, bajo una presión ma-nométrica de 40 atm. Determine la masa de oxígeno que se
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Answer:

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

Explanation:

Asúmase que el balón es rígido. Supongamos que el oxígeno se comporta como un gas ideal, entonces la ecuación de estado es la siguiente:

P\cdot V = \frac{m\cdot R_{u}\cdot T}{M} (1)

Donde:

P - Presión, medida en atmósferas.

V - Volumen, medido en litros.

m - Masa, medida en kilogramos.

M - Masa molar, medida en kilogramos por kilomol.

T - Temperatura, medida en Kelvin.

R_{u} - Constante de los gases ideales, medida en atmósfera-litros por kilomol-Kelvin.

El aire experimenta un proceso isocórico e isotérmico, entonces obtenemos la siguiente relación:

\frac{P_{1}}{m_{1}} = \frac{P_{2}}{m_{2}} (2)

Nótese que los subíndices 1 y 2 representan los estados inicial y final de proceso.

Si sabemos que P_{1} = 41\,atm, m_{1} = 12\,kg y P_{2} = 25\,atm, entonces la masa final del aire es:

m_{2} = \frac{P_{2}}{P_{1}} \cdot m_{1}

m_{2} = \left(\frac{25\,atm}{41\,atm}\right)\cdot (12\,kg)

m_{2} = 7.317\,kg

La masa que se ha extraído del balón es:

\Delta m = m_{1}-m_{2}

\Delta m = 12\,kg-7.317\,kg

\Delta m = 4.683\,kg

Quedan 7.317 kilogramos de oxígeno en el balón y se extraen 4.683 kilogramos de oxígeno en el proceso.

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