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dlinn [17]
3 years ago
5

A group consists of 10 men and 11 women. in how many ways can a team of exactly 4 men and 6 women be selected?

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0
C(10,4)×C(11,6) = 210×462 = 97,020

_____
Any of the choices of 4 of 10 men can be combined with any of the choices of 6 of 11 women. The "n choose k" function, C(n, k) is computed as n!/(k!×(n-k)!).
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See the graph below

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