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Butoxors [25]
3 years ago
12

The flag of a country contains an isosceles triangle.​ (Recall that an isosceles triangle contains two angles with the same​ mea

sure.) If the measure of the third angle of the triangle is 4545​° more than three times nbspthree times the measure of either of the other two​ angles, find the measure of each angle of the triangle.​ (Recall that the sum of the measures of the angles of a triangle is​ 180°.)
Mathematics
1 answer:
grin007 [14]3 years ago
8 0
Each angles opposite the legs are 67.5 degrees
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3^6 power. it would be 3 to the 6th power
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4 years ago
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3y-12x=24 and goes through point (2,-6) . write your answer in y=mx+b
Masteriza [31]

Answer:

y= 4x+8

Step-by-step explanation:

Add 12x to both sides.

3y=24+12x

The equation is in standard form.

3y=12x+24

Divide both sides by 3.

3

3y

​

=

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Dividing by 3 undoes the multiplication by 3.

y=

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Divide 24+12x by 3.

y=4x+8

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2 years ago
(3-p)^2<br> How to solve this steps
Zanzabum

Answer:

Look at the attachment

7 0
4 years ago
The ratio of the measures of the three angles in a tangle 3107. Find the measures of the angles and write them in size order,
N76 [4]

Answer:

27, 90 and 63

Step-by-step explanation:

Given

Ratio of triangle sides

Ratio = 3 : 10 : 7

Required:

The length of each side

Triangles in a triangle add up to 180.

The side with ratio 3 is:

S_1 = \frac{3}{3 + 10 + 7} *180

S_1 = \frac{3 *180}{20}

S_1 = \frac{540}{20}

S_1 = 27

The side with ratio 10 is:

S_2 = \frac{10}{3 + 10 + 7} *180

S_2 = \frac{10 *180}{20}

S_2 = \frac{1800}{20}

S_2 = 90

Lastly:

The side with 7 as its ratio

S_3 = \frac{7}{3 + 10 + 7} *180

S_3 = \frac{7 *180}{20}

S_3 = \frac{1260}{20}

S_3 = 63

Hence, the angles are: 27, 90 and 63

5 0
3 years ago
Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0
Softa [21]

The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

The equation of an ellipse centered at  (h,k) is

(x - h)²/a² + (y - k)²/b² (1) where a > b and the major axis is parallel to the x axis

Given x² + 16y² - 96y + 128 = 0, we convert it into the standard equation of an ellipse.

So, x² + 16y² - 96y + 128 = 0

Dividing through by 16, we have

x²/16 + 16y²/16  - 96y/16 + 128/16 = 0/16

x²/16 + y² - 6y + 8 = 0

Completing the square in y by adding and subtracting (-6/2)² = (-3)²

x²/16 + y² - 6y + (-3)² - (-3)² + 8 = 0

x²/16 + (y - 3)² - 9 + 8 = 0

x²/16 + (y - 3)² - 1 = 0

x²/16 + (y - 3)² = 1

x²/4² + (y - 3)²/1² = 1  (2)

Comparing equations (1) and (2), we have that a = 4 and b = 1.

Since a = 4 > b = 1, the major axis for the ellipse is the x-axis

So, the major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

Learn more about ellipse here:

brainly.com/question/26679189

#SPJ1

8 0
2 years ago
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