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3 years ago

Special Triangles

Mathematics

1 answer:

natulia [17]3 years ago

6 0

Since this is a 45-45-90 triangle, n = 9 and m = x

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PLZ HELP on THIS QUESTION

Greeley [361]

Its a rectangle cut the corners

8 0

3 years ago

: The proliferation of the Internet has given rise to a new method of advertising, called spamming, that essentially is a more c

Dmitry [639]

The number of potential customers that the company has reached is 10,000 e--mail addresses.

<h3>What is a word problem in mathematics?</h3>

A word problem is a real-life problem and it can be approached with the use of a mathematical model, interpretation into variables, and arithmetic operations usage.

Given that:

A company buys three mailing lists with 2500, 3500, and 4000 addresses respectively.

The number of potential customers that the company has reached is:

= 2500 3500 + 4000 e--mail addresses.

= 10,000 e--mail addresses.

Learn more about word problems here:

brainly.com/question/13818690

#SPJ1

8 0

2 years ago

Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points A and E. Lines BC and

Radda [10]

Answer: A

Step-by-step explanation:

3 0

1 year ago

What is the unit rate for 4543.08 km in 52.4 h? Enter your answer, as a decimal, in the box. km/h

sdas [7]

Plz mark me brainliest the answer is 86.7

hope this helps :)

8 0

3 years ago

Read 2 more answers

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

$y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}$

Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

7 0

3 years ago