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Helen [10]
3 years ago
11

Help plz i need the help

Mathematics
1 answer:
Naddik [55]3 years ago
7 0
I think it gives you the average og the data set. Im not totally sure but i think thats what it meanr.
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A paper container in the shape of a right circular cone has a radius of 3 inches and a height of 8 inches. Determine and state t
Scrat [10]

Given:

Radius of the cone = 3 inches

Height of the cone = 8 inches

To find:

The volume of the cone, in terms of  π.​

Solution:

We know that, the volume of a cone is:

V=\dfrac{1}{3}\pi r^2h

Putting r=3,h=8, we get

V=\dfrac{1}{3}\pi (3)^2(8)

V=\dfrac{1}{3}\pi (9)(8)

V=\dfrac{72}{3}\pi

V=24\pi

Therefore, the volume of the cone is 24\pi.

7 0
2 years ago
A wheel turns through 200 revolutions per minute. How fast does it turn in radians per second?
lana [24]

Answer:

In one second it turns 200 / 60 = 3 1/3 revolutions. Since one revolution is 360°, the answer is 6 2/3 π radians.

6 0
3 years ago
Read 2 more answers
Can someone help me with both of these? What do I do with the 68 and 79?
Nutka1998 [239]
What he said just click on that
3 0
2 years ago
7. The scale on a map of Florida is 1 ⅛ inches to 25 miles. The distance on the map from Gainesville to Ocala is 1 ⅝ inches. Bas
sergij07 [2.7K]

Answer:

Since I figure you don't need this answer anymore, I'm just using it for free pts

Step-by-step explanation:

8 0
2 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
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