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weeeeeb [17]
4 years ago
11

What’s the value of x???

Mathematics
1 answer:
egoroff_w [7]4 years ago
6 0

Answer:

i believe it would be d square root of 17

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In the figure below, what is the length of PS in terms of x please help
3241004551 [841]

Answer:

B) x+22

Step-by-step explanation:

PS= PQ+QR+RS

PS= 2x+4+8+10-x

PS= x+22

Hope this helps you.

8 0
3 years ago
Read 2 more answers
$30,000 for 15 years at a yearly simple interest rate of 5%
djverab [1.8K]
Hi there

To find the simple interest earned
Use this formula
I=prt
I interest earned?
P principle 30000
R interest rate 0.05
T time 15 years

So
I=30,000×0.05×15
I=22,500

Hope it helps
8 0
3 years ago
the function g(x) Is the graph below resulted from shifting the graph of f(x) down 2 units. If f’(2)=8, what is g’(2)?
Sauron [17]

We know that the graph of g(x) is the result of a shift of 2 units down from f(x).

Then, f(x) and g(x) are related by:

g(x)=f(x)-2

Taking the derivative:

g^{\prime}(x)=f^{\prime}(x)

This is because the derivative of a constant number is 0. Finally, evaluating at x = 2:

\begin{gathered} g^{\prime}(2)=f^{\prime}(2) \\  \\ \therefore g^{\prime}(2)=8 \end{gathered}

4 0
1 year ago
What is the measure of each exterior angle of a decagon?
NemiM [27]
The sum of all of the exterior angles of any regular polygon is 360  (I'm assuming by decagon you mean a regular dodecagon).

Because the total has to be 360, and a decagon has 10 sides, you divide 360 by 10 to get each exterior angle.

360 ÷ 10 = 36, so each exterior angle of a decagon is 36 degrees.
3 0
4 years ago
suppose that incomes of families in Newport Harbor are normally distributed with a mean of $750,000 and a standard deviation of
denis23 [38]

Answer: 0.345

Step-by-step explanation:

Given : The incomes of families in Newport Harbor are normally distributed with Mean : \mu=\$ 750,000 and Standard deviation : \sigma= $250,000

Samples size : n=4

Let x be the random variable that represents the incomes of families in Newport Harbor.

The z-statistic :-

z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x= $800,000

z=\dfrac{800000-750000}{\dfrac{250000}{\sqrt{4}}}=0.4

By using the standard normal distribution table , we have

The probability that the average income of these 4 families exceeds $800,000 :-

P(x>80,000)=P(z>0.4)=1-P(z\leq0.4)\\\\=1-0.6554217=0.3445783\approx0.345

Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345

6 0
4 years ago
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