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Mashcka [7]
3 years ago
11

Gavin wrote the equation p = StartFraction 3 (s + 100) Over 4 EndFraction to represent p, the profit he makes from s sales in hi

s lawn-mowing business. Which equation is solved for s? s = StartFraction p minus 100 Over 3 EndFraction s = StartFraction 4 p minus 300 Over 3 EndFraction s = StartFraction 4 p Over 300 EndFraction s = StartFraction 400 p Over 3 EndFraction
Mathematics
2 answers:
Degger [83]3 years ago
4 0

Given the equation p = 3(s + 100)/4 

Where,

p = profit made

s = sales 

Solving for s from the given equation

p = 3(s + 100)/4

Multiply both sides by 4

4p = 3(s + 100)

4p = 3s + 300

Subtract 300 from both sides of the equation

4p – 300 = 3s

Same as, 3s = 4p – 300

s = (4p – 300)/3 

OR, s = 4p/3 – 100 

If any of these two is in the options, it’s the right answer.

adell [148]3 years ago
3 0

Answer:

the answer is b

Step-by-step explanation:

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nadezda [96]
D is the correct answer
5 0
4 years ago
For the function g(x)=3-8(1/4)^2-x
Reika [66]

Using function concepts, it is found that:

  • a) The y-intercept is y = 2.5.
  • b) The horizontal asymptote is x = 3.
  • c) The function is decreasing.
  • d) The domain is (-\infty,\infty) and the range is (-\infty,3).
  • e) The graph is given at the end of the answer.

------------------------------------

The given function is:

g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}

------------------------------------

Question a:

The y-intercept is g(0), thus:

g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3

--------------------------------------------------

\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty

Thus, the horizontal asymptote is x = 3.

--------------------------------------------------

Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

--------------------------------------------------

Question d:

  • Exponential function has no restrictions in the domain, so it is all real values, that is (-\infty,\infty).
  • From the limits in item c, the range is: (-\infty,3)

--------------------------------------------------

The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0
3 years ago
please help!!!!!!!!!!! Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogra
kondaur [170]
A=bh

330=22h

all you gotta do is divide by 22 on both sides 

330/22=h

H=15

and to test it out do 22*15 which equals 330
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Angie needs to buy 156 candles for a party instead each package has 8 candles how many packages should angie buy
Annette [7]
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Read 2 more answers
Which equation is perpendicular to the line y=5x-9
Soloha48 [4]

Answer:

The format of the equation of a line is y=mx+c so in order to know whether which line is perpendicular to line y=5x-9, gradient of y=5x-9,which is 5,has to multiply by another gradient to get -1.[in short m1×m2=-1]

So the equation perpendicular to line y=5x-9 has a gradient of -1÷5=-1/5

4 0
3 years ago
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