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poizon [28]
4 years ago
14

When 27x^2z/-3x^2z^6 is completely simplified, the exponent on the variable z is _____.

Mathematics
1 answer:
Savatey [412]4 years ago
7 0
<span>The expression given (27x^2)z/(-3x^2)(z^6), can be simplify as below:

 By properties of powers, if you have the same base, you can substract the exponents. Then:

 =(</span>27x^2)z/(-3x^2)(z^6)
 =-9z/z^6  (As you can see: x^2-2= x^0=1)
 =-9/z^5    (Then, z^6-1=z^5)
<span>
 Therefore, the answer is: The exponent on the variable z is 5.</span> 
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4 years ago
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Olenka [21]

Answer:

you know that sin 90 is 1 and cos 45 is 1/√2

so,

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7 0
3 years ago
Need help with this question. ​
solniwko [45]

We have this equation:

\log(x) + \log(x + 99) = 2

First, combine both logarithms using the multiplication property and simplify the expression.

\log[x(x + 99)] = 2

\log[ {x}^{2} + 99x ] = 2

Now, use the definition of logarithm to transform the equation.

{10}^{2}  =  {x}^{2}  + 99x

{x}^{2}   +  99x  -  100 = 0

Finally, use the quadratic formula to solve the equation.

x =  \frac{ -99 ± \sqrt{ {99}^{2}  - 4 \times 1 \times ( - 100)} }{2 \times 1}

With this, we can say that the solution set is:

  • x = 1
  • x = -100

We cannot choose x = -100 as a solution because we cannot have a negative logarithm. The only solution is x = 1.

8 0
2 years ago
How to determine if a fraction is repeating or terminating?
kolbaska11 [484]

If you do long division of the numerator and nominator, if the remainder is 0, the decimal form is terminating. If the remainder is non-zero, it will be a repeating decimal...

5 0
3 years ago
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



5 0
4 years ago
Read 2 more answers
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