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iren2701 [21]
3 years ago
11

Please do this questions its for 100 point will chose brainiest do in full please

Mathematics
2 answers:
sertanlavr [38]3 years ago
5 0

Answer:

e) x^2-17x+72  ......  multiply two binomials

f)  6x(x^3-2)   ......... common  factoring

g) (x+6)(x+2)    .............factor a trinomial

h) x^2+12x+35 ......  multiply two binomials

i)  (x+6)(x-6)  ................difference of squares

Step-by-step explanation:

e)

(x-8)(x-9)

=x(x-9)-8(x-9)

=x^2-9x-8x+72

=x^2-17x+72  ......  multiply two binomials

f)

6x^4-12x

= 6(x^4 - 2x)

= 6x(x^3-2)   ......... common  factoring

g)

x^2+8x+12

= x^2+2x +6x+12

= x(x+2) + 6(x+2)

= (x+6)(x+2)    .............factor a trinomial

h)

(x+7)(x+5)

=x^2+5x + 7x +35

= x^2+12x+35 ......  multiply two binomials

i)

x^2 - 36

= (x+6)(x-6)  ................difference of squares

Dafna1 [17]3 years ago
4 0

Answer:

\boxed{\mathrm{view \: explanation}}

Step-by-step explanation:

(e) (x-8)(x-9)

     Multiplying two binomials.

    x(x-9)-8(x-9)

    x² -9x - 8x + 72

    x² - 17x + 72

(f) 6x⁴ - 12x

   Common factoring.

   6x(x³ - 2)

(g) x² + 8x + 12

     Factoring trinomial of the form ax² + bx + c.

    x² +2x + 6x + 12

    x(x + 2) + 6(x + 2)

    (x + 2) (x + 6)

(h) (x + 7)(x + 5)

     Multiplying two binomials.

    x(x + 5)+7(x + 5)

     x² + 5x + 7x + 35

    x² + 12x + 35

(i) x² - 36

    Difference of two squares.

   a² - b² = (a + b)(a - b)

    x² - 6²

   a = x,    b = 6

    (x + 6)(x - 6)

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The product of a number and -8 gives eight times the sum of that number and 36. Find that number
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Answer:

-18

Step-by-step explanation:

Let x be our number. First we have to write our equation.

The product of a number and -8 is represented as -8x (-8 multiplied by x). Remember that 'product' signifies multiplication.

The result is eight times the sum of x and 36. This is represented as 8(x + 36). We add x and 36 first because 8 has been multiplied by the sum of those two numbers.

So our equation is:

-8x = 8(x + 36)

We can now solve for x. First, expand the bracket.

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Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

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