All categories

2 years ago

Can i get some help with this

Mathematics

1 answer:

Olegator [25]2 years ago

7 0

If we draw RU and RT we see the radii are perpendicular to the tangents, so TRU and TZU are supplementary. Since TZU=XZY=15 degrees, TRU=180-15=165 degrees. So the other side is 360-165=195 degrees as is the measure of arc TSU

Answer: 195 degrees

You might be interested in

A cone ha a volume of 27 pi cm cubed and a radius of 3 cm what is the height of the cone

vampirchik [111]

I answered this before and explained this but the answer is 3π I think. Hope this helps

7 0

3 years ago

PLEASE HELP I WILL GIVE BRAINLEIST

lina2011 [118]

Answer:

They help you see progressions but sometimes graphs can be manipulated to convey specific data and hide others like using methods called cherry picking, changing x and y axis and etc.

7 0

3 years ago

Variable y varies directly with variable x. If x = 12, then y = 3. What is the value of y

Monica [59]

Answer:

Step-by-step explanation:

To find the value of y when x = 8 we must first find the relationship between the two variables.

The statement

y varies directly with variable x is written as

y = kx

where k is the constant of proportionality

when

x = 12

y = 3

Substitute the values into the above formula and solve for k

That's

3 = 12k

Divide both sides by 12

$k = \frac{1}{4}$

So the formula for the variation is

$y = \frac{1}{4} x$

when

x = 8

$y = \frac{1}{4} \times 8$

we have the final answer as

Hope this helps you

5 0

3 years ago

Please show all steps... finals coming up!

Rama09 [41]

1) find x
y=1/(x+3) -4
y+4=1/(x+3) -4+4
y+4=1/(x+3)

x+3 =1/(y+4)
x= 1/(y+4) - 3

2) change x on y , and y on x

x= 1/(y+4) - 3
y= 1/(x+4) - 3 This is an answer.

4 0

3 years ago

Find y as a function of x if y"' + 9y' = 0, y(0) = 6, y'(0) = 9, y"(0) = 18. y(x) =

Andreas93 [3]

Answer:

y(x) = 8 - 2cos 3x + 3sin 3x

Step-by-step explanation:

Given the equation:

y''' + 9y' = 0

The characteristic equation :

⇒r³ + 9r =0

Solving for r, we get r = 0 and r = ± 3i

The general equation for such equation is :

y = C₁ + C₂cos 3x + C₃sin 3x

Given:

y(0) = 6

Thus, Applying in the above equation, we get

6 = C₁ + C₂ .......................................................1

Differentiating y , we get:

y' = -3C₂sin 3x + 3C₃cos 3x

Given:

y'(0) = 9

Thus, Applying in the above equation, we get

9 = 3C₃

or,

C₃ = 3

Differentiating y' , we get:

y'' = -9C₂cos 3x - 9C₃sin 3x

Given:

y''(0) = 18

Thus, Applying in the above equation, we get

18 = -9C₂

or,

C₂ = -2

Applying in equation 1 , we get:

C₁ = 8

Thus,

y(x) = 8 - 2cos 3x + 3sin 3x

4 0

3 years ago