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Gelneren [198K]
3 years ago
9

If the coordinates of point A are (8 , 0) and the coordinates of point B are (3 , 7), the y-intercept of AB is ___

Mathematics
1 answer:
JulsSmile [24]3 years ago
9 0

Answer:

a) y-intercept of AB is 56/5

b) equation of line CD is:

y = -7/5x + 12

Step-by-step explanation:

a) If the coordinates of point A are (8 , 0) and the coordinates of point B are (3 , 7), the y-intercept of AB is ___

We are given the points A(8,0) and point B (3,7)

We need to find y-intercept i.e b

Finding slope of points A and B = y₂ - y₁/x₂ - x₁

=7-0/3-8

=7/-5

= - 7/5

So, finding y intercept b by using equation

y = mx+b

And considering point A (8,0) x = 8 and y = 0 and m = -7/5

0 = 8(-7/5) + b

0 = -56/5 + b

=> b = 56/5

So, y-intercept of AB is 56/5

b) If the coordinates of point D are (5 , 5), the equation of line CD is y = __

Since AB || CD

both will have same slope

i.e m = -7/5

we need to find y-intercept given point D (5,5)

y = mx+b

5 = -7/5(5)+b

5 = -7 + b

=> b = 5+7

=> b = 12

So, equation of line CD is:

y = -7/5x + 12

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Bess [88]

Answer:

Its 3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the midpoint of the segment with the endpoints:(-7,-8) and (4,7)
Oxana [17]

Answer:  (-1.5, -0.5)

Step-by-step explanation:

8 0
3 years ago
Encuentra el numero decimal equivalente a la fracción
Artyom0805 [142]

7/10 = 0.7

198/100 = 1.98

85/100 = 0.85

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1/4 = 0.25

3/2 = 1.5

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Hope it Helps!

¡Espero eso ayude!

3 0
3 years ago
Someone help me please. i’ll give you brainliest. how do i solve it.
tresset_1 [31]
Its a guess and check problem you have to just try to find a combonation of 8 and 10 to get 200
7 0
3 years ago
The value of a car depreciates by 40% each year. At the end of 2007 the value of the car was £3600 Work out the value of the car
natima [27]

Answer: $6,000

Step-by-step explanation: If set up correctly, the value of the car at the end of 2006 times 0.6 (because the car is losing 0.4 of its value, so it keeps 0.6 of its value) should get you the value of the car at the end of 2007.

The equation should look like this:

(value of the car at the end of 2006) x 0.6 = (value of the car at the end of 2007)

Then you substitute: (value at the end of 2006) x 0.6 = 3600

Then divide: (value at the end of 2006) = 0.6 ÷ 3600

Then substitute again: (value at the end of 2006) = 6,000

Hope this helped you! Feel free to ask me any questions!

3 0
3 years ago
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