Question

Jupiter has a mass of about 318 times the mass of Earth and a diameter of about 11.2 times the diameter of Earth. The acceleration of a body falling near the surface of Jupiter is about A : 24.8 m/s2 B : 278 m/s2 C : 9.80 m/s2 D : 3.87 m/s2 E : 0.345 m/s2

Answer 1

Answer:

(a) 24.8 m/$src^2$

Explanation:

acceleration due to gravity is given by $g=\frac{GM}{R^2}=9.8 m/sec^2$

where G is gravitational constant M is mass of earth and R is radius of earth

it is given that mass of Jupiter is =318 M

and radius of earth =11.2 R

$g_{jupiter}=\frac{318GM}{11.2^2\times R^2}=2.535\times 9.8=24.84375 m/sec^2$

so the acceleration due to gravity at Jupiter is 24.8 m/$sec^2$ so option a will be correct answer